Shell Programming and Scripting

I have a string 1234567890
My requirement is to replace the characters between position 6 and 8 (both positions inclusive)
with a string KUMARJIT
i.e.,
1234567890 should change to 12345KUMARJIT90
I am using korn shell and linux 2.6x OS , and I want to do it using sed.

I made it till this far :

Code:

echo 1234567890 | sed -n -e 's/^\(.\{6\}\)/KUMARJIT'

only to replace the first 6 characters with KUMARJIT
but thats not what I need .
I looked accross numerous sed examples online , many of them had hiflying regexp written , but none bothered to take the pain
and explain what the code actually does .
Its an earnest request , please guide me through you posts in case you are replying .
I am still a Unix novice.
Thanks
Kumarjit.

Will this do? awk no sed

Code:

echo "1234567890" | awk '{print substr($1,1,5) "KUMARJIT" substr($1,9,99)}'
12345KUMARJIT90

If you are on Linux, your ksh is most likely a kornshell 93. If so, this should work

Code:

$ str=1234567890
$ str=${str:0:5}KUMARJIT${str:8:2}
$ print $str
12345KUMARJIT90

---------- Post updated at 14:05 ---------- Previous update was at 14:03 ----------

Explanation:

${str:x:y} takes a substring out of str, where x ist the start index (starting at 0) and y is the length of the substring in characters.

Works also in bash

Code:

str=1234567890
str=${str:0:5}KUMARJIT${str:8:2}
echo $str
12345KUMARJIT90

Code:

$ echo 1234567890 | sed -n -e 's/\(.\{5\}\)...\(.*\)/\1KUMARJIT\2/p'
12345KUMARJIT90

How about Perl ?

Code:

 
echo '1234567890 should change to 12345KUMARJIT90' | perl -pe 'substr($_,5,3)="KUMARJIT";'

Just another lazy one

Code:

# echo 1234567890 | sed 's/^\(.....\).../\1KUMARJIT/'
12345KUMARJIT90