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UNIX - requirement

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# 1  
Old 06-17-2013
UNIX - requirement
Hi All,
I have a source file with data

Code:
Name ~ Groups
Muni~abc,was,USA_ax,123
Chaitanya~USA_12,was
Balaji~123,xyz,was
Ramu~123,xyz

From the second column i want to extract only the groups that matches the pattern 'USA_%' or if the group = 'was', and ignore any other columns.


********Expected output ***********
Code:
Name | Groups
Muni|was,USA_ax
Chaitanya|USA_12,was
Balaji|was
Ramu|

How can I do this in UNIX
Last edited by Scrutinizer; 06-17-2013 at 12:45 AM.. Reason: code tags for data samples
# 2  
Old 06-17-2013
What have you tried so far? Share your thoughts to solve this problem.
# 3  
Old 06-17-2013
I am not have any idea about this .Thinking how can I do this by grep
# 4  
Old 06-17-2013
grep is definitely not an option as I see your expected output has different field separator.

I would suggest using awk instead:
Code:
awk -F'[~,]' '
        NR == 1 {
                sub ( /~/, "|" )
        }
        NR > 1 {
                s = $1 "|"
                for( i = 2; i <= NF; i++ )
                {
                        if( $i == "was" || $i ~ /USA.*/ )
                                s = s $i OFS
                }
                sub( /,$/, X, s )
                $0 = s
        }
        1
' OFS=, file

# 5  
Old 06-17-2013
It cannot be done with grep, because the input needs to be transformed..
# 6  
Old 06-17-2013
great logic. Thanks a lot

---------- Post updated at 12:50 PM ---------- Previous update was at 12:26 AM ----------

i hope for removing last character "," you have used this
Code:
sub( /,$/, X, s )

what is the purpose of 1 here .just curious to know the logic .Is it for printing ?

Code:
  NR > 1 {
                s = $1 "|"
                for( i = 2; i <= NF; i++ )
                {
                        if( $i == "was" || $i ~ /USA.*/ )
                                s = s $i OFS
                }
                sub( /,$/, X, s )
                $0 = s
        }
        1

Last edited by Scrutinizer; 06-17-2013 at 02:52 PM.. Reason: code tags
# 7  
Old 06-17-2013
Yes, it is for printing. It's a logical expression that determines whether a line gets printed or not. It could be any expression technically, but a '1' makes it always print.
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