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Syntax error near unexpected token `else'

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# 1  
Old 05-22-2013
Syntax error near unexpected token `else'
Hi,

I am trying to read the session log through script. But it keeps showing me some error near. I have tried everything. Even tried converting the script using sed command to remove the hidden characters(\r).But nothing seems to be working.Below is the script :

Code:
#!/bin/bash
cd /app/Informatica/INFA95/server/infa_shared/SessLogs
grep -A 20 'SESSION LOAD SUMMARY' s_m_SCENARIO_3.log > abc.txt
rm s_m_SCENARIO_3.log
cd..
count=0
cat abc.txt | while read line
do
if[ $count -eq 1 ]then
echo " source records " >> record.txt
echo $line | grep 'Output Rows' >> record.txt
elif[ $count - eq 2 ]then
echo " target records" >> record.txt
echo $line | grep 'Output Rows' >> record.txt
else
echo "nothing"
fi
echo $line | grep -nF 'Instance Name: [SQ_'
if [ $? -eq 0 ]
then
count=1
elif
echo $line | grep 'Instance Name'
count=2
else
count=0
fi
done


Thank You in advance for you help Smilie
# 2  
Old 05-22-2013
Use code tags for code please.

You need spaces on either side of the [ and ], you can't let them touch other characters. You can't put 'then' on the same line without a ; inbetween. You need a then for elif, too.

Code:
if [ ... ]
then
...
elif [ ... ]
then
...
else
...
fi

# 3  
Old 05-23-2013
Thanks for replying Corona688.

I have kept proper spaces between [ and ], when i keep then in the next line it gives me the same error

"syntax error near unexpected token `then'

Lastly i have used a then after elif too, its just not placed in the next line.

---------- Post updated at 02:29 PM ---------- Previous update was at 02:25 PM ----------

Thank you soo much Corona688 it worked

---------- Post updated 05-23-13 at 05:53 AM ---------- Previous update was 05-22-13 at 02:29 PM ----------

Hi ,
My Script is working now but it is showing too many arguments Smilie

Code:
count=0
cat abc.txt | while read line
do
if [ $count -eq 1 ]
then
echo " source records " >> record.txt
echo $line | grep 'Output Rows'  >> record.txt
elif [ $count - eq 2 ]
then
echo " target records" >> record.txt
echo $line | grep 'Output Rows' >> record.txt
else
echo "nothing"
fi
echo $line | grep -nF 'Instance Name: [SQ_'
if [ $? -eq 0 ]
then
count=1
elif echo $line | grep 'Instance Name'
then
count=2
else
count=0
fi
done

Thanks,
Gaurav
Last edited by Scott; 05-23-2013 at 08:00 AM.. Reason: Please use code tags
# 4  
Old 05-23-2013
Quote:
Originally Posted by Aryan12345
Thanks for replying Corona688.

I have kept proper spaces between [ and ], when i keep then in the next line it gives me the same error

"syntax error near unexpected token `then'

Lastly i have used a then after elif too, its just not placed in the next line.

---------- Post updated at 02:29 PM ---------- Previous update was at 02:25 PM ----------

Thank you soo much Corona688 it worked

---------- Post updated 05-23-13 at 05:53 AM ---------- Previous update was 05-22-13 at 02:29 PM ----------

Hi ,
My Script is working now but it is showing too many arguments Smilie

Code:
count=0
cat abc.txt | while read line
do
if [ $count -eq 1 ]
then
echo " source records " >> record.txt
echo $line | grep 'Output Rows'  >> record.txt
elif [ $count - eq 2 ]
then
echo " target records" >> record.txt
echo $line | grep 'Output Rows' >> record.txt
else
echo "nothing"
fi
echo $line | grep -nF 'Instance Name: [SQ_'
if [ $? -eq 0 ]
then
count=1
elif echo $line | grep 'Instance Name'
then
count=2
else
count=0
fi
done

Thanks,
Gaurav
Change [ $count - eq 2 ] to [ $count -eq 2 ].
This User Gave Thanks to Don Cragun For This Post:
Aryan12345
# 5  
Old 05-23-2013
Thanks Corona688 Smilie
# 6  
Old 05-23-2013
That was Don Cragun this time. Smilie
# 7  
Old 05-23-2013
Ohhh , Thanks Don Smilie
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