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Find and replace from an XML

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# 1  
Old 05-15-2013
Lightbulb Find and replace from an XML
Input-xml
Code:
<weblogic-web-app>
  <session-descriptor>
    <session-param>
      <param-name>SysName</param-name>
      <param-value>smilyface</param-value>
    </session-param>
    <session-param>
      <param-name>InternetProtocol</param-name>
      <param-value>xxxxxxxx</param-value>
    </session-param>
    <session-param>
      <param-name>Timeout</param-name>
      <param-value>600s</param-value>
    </session-param>


I have a number of xml files in each systems. I need to replace xxxxxxxx with the system IP

Note:
1. The value xxxxxxxx may be different in each xml files.
2. The value InternetProtocol will be same for each xml files.

Smilie
Last edited by linuxadmin; 05-15-2013 at 03:59 AM.. Reason: code tag added
# 2  
Old 05-15-2013
Code:
awk '/InternetProtocol/ {print; getline; gsub($0,"<IP>")}{print}' <filename>

Last edited by Franklin52; 05-15-2013 at 04:33 AM.. Reason: Please use code tags
# 3  
Old 05-15-2013
awk
Quote:
Originally Posted by dddkiran
awk '/InternetProtocol/ {print; getline; gsub($0,"<IP>")}{print}' <filename>
Please use code tag for code and data samples.

Try smth like this.

Code:
awk -v ip=$(hostname -i) '/InternetProtocol/{print;getline;ip=">"ip"<";sub(/>.*</,ip);}1' input_file

Cheers!!!
-R
This User Gave Thanks to rangarasan For This Post:
linuxadmin
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