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awk to print record not equal specific pattern

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# 1  
Old 05-02-2013
Lightbulb awk & get any line with ( specific charactors from pattern )
how to use "awk" to print any record has pattern not equal ? for example my file has 5 records & I need to get all lines which $1=10 or 20 , $2=10 or 20 and $3 greater than "130302" as it shown :

Code:
10  20  1303252348212B030 
20  10  1303242348212B030 
40  34  1303252348212B030 
10  20  1303032348212B030 
10  20  1303022348212B030

I have tried below

Code:
awk '( $1 ~/[12]0/  ||  $2 ~/[12]0 ) && $3 ! ~/130302/ { print $0 }'  my file

I think awk is confused with the digits after 130302XXXXXX !!!!
Last edited by Scott; 05-06-2013 at 09:04 PM.. Reason: More code tags
# 2  
Old 05-02-2013
First of all I didn't understand your requirement clearly.

But I noticed few syntax error in your code:
Code:
awk '( $1 ~ /[12]0/  ||  $2 ~ /[12]0/ ) && $3 !~ /130302/ { print $0 }' myfile

This User Gave Thanks to Yoda For This Post:
arm
# 3  
Old 05-02-2013
dear as far as I know nothing wrong with backslash / and not equal ! =
my request is to get following output :
Code:
10  20  1303252348212B030 
20  10  1303242348212B030 
10  20  1303032348212B030

from below input
Code:
10  20  1303252348212B030 
20  10  1303242348212B030 
40  34  1303252348212B030 
10  20  1303032348212B030 
10  20  1303022348212B030

Last edited by Franklin52; 05-03-2013 at 03:15 AM.. Reason: Code tags
# 4  
Old 05-02-2013
Code:
$ awk '($1 ~ /[12]0/ || $2 ~ /[12]0/) && substr ($3, 0, 6) > 130302 { print }' input
10 20 1303252348212B030
20 10 1303242348212B030
10 20 1303032348212B030

# 5  
Old 05-02-2013
Quote:
Originally Posted by arm
dear as far as I know nothing wrong with backslash / and not equal ! =
Ok so there is nothing wrong with backslash:
Code:
awk '$2 ~ /[12]0' myfile
 syntax error The source line is 1.
 The error context is
                $2 ~ >>>  /[12]0 <<<

And there is nothing wrong with regexp not matching:
Code:
awk '$2 ! ~/[12]0' myfile
 syntax error The source line is 1.
 The error context is
                $2 ! >>>  ~ <<<

I hope then you have some explanation for above behavior?
This User Gave Thanks to Yoda For This Post:
arm
# 6  
Old 05-02-2013
Quote:
Originally Posted by hanson44
Code:
$ awk '($1 ~ /[12]0/ || $2 ~ /[12]0/) && substr ($3, 0, 6) > 130302 { print }' input
10 20 1303252348212B030
20 10 1303242348212B030
10 20 1303032348212B030

can you explain
Code:
substr ($3, 0, 6) > 130302

---------- Post updated at 05:04 PM ---------- Previous update was at 05:02 PM ----------

Quote:
Originally Posted by Yoda
Ok so there is nothing wrong with backslash:
Code:
awk '$2 ~ /[12]0' myfile
 syntax error The source line is 1.
 The error context is
                $2 ~ >>>  /[12]0 <<<

And there is nothing wrong with regexp not matching:
Code:
awk '$2 ! ~/[12]0' myfile
 syntax error The source line is 1.
 The error context is
                $2 ! >>>  ~ <<<

I hope then you have some explanation for above behavior?
do this
Code:
awk '$2 ~ /[12]0/' myfile

and this
Code:
awk '$2 ! ~/[12]0/' myfile

you still have error message ?
# 7  
Old 05-02-2013
Quote:
Originally Posted by Yoda
Ok so there is nothing wrong with backslash:
Code:
awk '$2 ~ /[12]0' myfile
 syntax error The source line is 1.
 The error context is
                $2 ~ >>>  /[12]0 <<<

And there is nothing wrong with regexp not matching:
Code:
awk '$2 ! ~/[12]0' myfile
 syntax error The source line is 1.
 The error context is
                $2 ! >>>  ~ <<<

I hope then you have some explanation for above behavior?
Try nawk instead of awk. On some systems, plain awk is very, very old.
This User Gave Thanks to Corona688 For This Post:
arm
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