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awk set $1 to itself, effect on $0
04-28-2013
awk '{$1=$1} /^[0-9]+$/' file$ cat test.sh
set -v
echo " abcd" | awk '{ print ":" $0 ":" }'
echo " abcd" | awk '{ print ":" $1 ":" }'
echo " abcd" | awk '{ $0=$0; print ":" $0 ":" }'
echo " abcd" | awk '{ $0=$0; print ":" $1 ":" }'
echo " abcd" | awk '{ $1=$1; print ":" $1 ":" }'
echo " abcd" | awk '{ $0=$1; print ":" $0 ":" }'
echo " abcd" | awk '{ $0=$1; print ":" $1 ":" }'
echo " abcd" | awk '{ $1=$0; print ":" $0 ":" }'
echo " abcd" | awk '{ $1=$0; print ":" $1 ":" }'
echo " abcd" | awk '{ $1=$1; print ":" $0 ":" }'$ ./test.sh
echo " abcd" | awk '{ print ":" $0 ":" }'
: abcd:
echo " abcd" | awk '{ print ":" $1 ":" }'
:abcd:
echo " abcd" | awk '{ $0=$0; print ":" $0 ":" }'
: abcd:
echo " abcd" | awk '{ $0=$0; print ":" $1 ":" }'
:abcd:
echo " abcd" | awk '{ $1=$1; print ":" $1 ":" }'
:abcd:
echo " abcd" | awk '{ $0=$1; print ":" $0 ":" }'
:abcd:
echo " abcd" | awk '{ $0=$1; print ":" $1 ":" }'
:abcd:
echo " abcd" | awk '{ $1=$0; print ":" $0 ":" }'
: abcd:
echo " abcd" | awk '{ $1=$0; print ":" $1 ":" }'
: abcd:
echo " abcd" | awk '{ $1=$1; print ":" $0 ":" }'
:abcd:
04-28-2013
I understood about $0 being rebuilt. Now that I think about it more, it makes sense that when $0 is rebuilt, the only input is $1 so the new version of $0 has no blanks. Thanks.|
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