Print lines with numbers only.


 
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# 1  
Old 04-28-2013
Print lines with numbers only.

Is there other way then this only solution I have found to print lines with numbers only?

file.txt
Code:
one
two
three
3
four
five
5tt
6gfjdfgdf
9
66
six
0
seven
7
eight
546546
gffdg445gfg
fd644
0112

Code:
awk '{n=$1/1; if(n==$1)print}' file.txt
3
9
66
0
7
546546
0112

# 2  
Old 04-28-2013
Code:
$ sed -n "/^[0-9]\+$/ p" file.txt
3
9
66
0
7
546546
0112

# 3  
Old 04-28-2013
Thanks
From you input I see that this works on awk
Code:
awk '/^[0-9]+$/' file.txt

# 4  
Old 04-28-2013
Yes, that would work perfectly.
# 5  
Old 04-28-2013
Just bear in mind that a line would not be selected if there is so much as single space at the beginning or the end. An alternative would be:
Code:
awk 'NF==1 && $1~/^[0-9]+$/' file

# 6  
Old 04-28-2013
In that case, if blanks allowed:
Code:
$ awk '/^ *[0-9]+ *$/' file.txt
3
9
66
0
7
546546
0112

# 7  
Old 04-28-2013
Yes, but the then it would be better to use
Code:
awk '/^[ \t]*[0-9]+[ \t]*$/' file

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