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Shell Programming and Scripting

Find string in variable

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# 1  
Old 04-22-2013
Display Find string in variable
korn shell,

testing if a pattern exist in a string,
x is constant, y could be none,all or any combination of the elements of x,

Code:
x="aa bb cc dd ee ff gg hh ii jj kk ll"
y="ff kk"
for z in `echo ${x}`
do
 if [ <any pattern in $y matches any pattern in $x> ]
   then
     do something
 fi
done

Last edited by Scrutinizer; 04-22-2013 at 07:07 PM.. Reason: code tags
# 2  
Old 04-22-2013
Try:
Code:
for z in $x
do
  case $y in
    *$z*) echo "a pattern in \$y matches any pattern in \$x"; break
  esac
done

This User Gave Thanks to Scrutinizer For This Post:
squrcles
# 3  
Old 04-22-2013
Recent kshs (as well as bashes) provide a regex match in conditional expressions. man ksh:
Quote:
Conditional Expressions.
A conditional expression is used with the [[ compound command to test attributes of files and to compare strings. Field splitting and file name generation are not performed on the words between [[ and ]]. Each expression can be constructed from one or more of the following unary or binary expressions: . . .
string =~ ere
True if string matches the pattern ~(E)ere where ere is an extended regular expression.
So your code could read:
Code:
x="aa bb cc dd ee ff gg hh ii jj kk ll"
y="ff kk"
$ for z in $x; do [[ "$y" =~ "$z" ]] && echo $z; done
ff
kk

Aside: that `echo ${x}` is pointless - get rid of it.
This User Gave Thanks to RudiC For This Post:
squrcles
# 4  
Old 04-22-2013
If 'pattern' stands for 'word' and 'match' for 'is equal to', then nested loops seem most correct.
Code:
for x1 in $x; do
 for y1 in $y; do
  if [ "$x1" = "$y1" ]; then
   echo "$x1"
  fi
 done
done

This User Gave Thanks to MadeInGermany For This Post:
squrcles
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