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Selective Replace awk column values

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# 1  
Old 04-10-2013
Selective Replace awk column values

Hi, I have the following data:

I want to selective replace the value of the 15th field with another value:
Lets say:

awk 'BEGIN{OFS=FS="|"} $15 ="NEGATIVE"{$15="3"} {print $1"|"$2"|"$3"|"$4"|"$5"|"$6"|"$7"|"$8"|"$9"|"$10"|"$11"|"$12"|"$13"|"$14"|"$15"|" }' test.txt

But on execution I get this output:[everything in the 15th filed gets replaced.


How to correct selective replace those values?

Thanks a lot for your help!
# 2  
Old 04-10-2013
awk -F\| '{sub("\"NEGATIVE\"",3,$15);sub("\"NEG-DID\"",2,$15);sub("\"NEG-WARN\"",4,$15)}1' OFS="|" test.txt

This User Gave Thanks to Yoda For This Post:
# 3  
Old 04-10-2013
#cat variable.txt
# cat file.txt
#awk -F"|" 'NR==FNR{split($0,a,"=");arr[a[1]]=a[2];next}
$15=arr[$15]}1' OFS="|" variable.txt file.txt

This User Gave Thanks to pravin27 For This Post:
# 4  
Old 04-11-2013

$ uname
$ cat fil1
$ cat fil2
$ awk -F= -v c='"' NR='=FNR{a[c $1 c]=$2;next}{for(i in a)/i/sub(i,a[i],$0)}1' fil2 fil1

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