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Shell Programming and Scripting

Selective printing

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# 1  
Old 03-04-2013
Selective printing
I have the following contents in a file

Code:
---- CRITICAL: altered for /usr/bin/bin1 ---- OK: /usr/sbin/bin2  result fine ---- OK: /usr/sbin/bin3 result fine ---- CRITICAL: altered for /usr/bin/bin4 ---- OK: /usr/bin/bin5 result fine ---- OK: /usr/bin/bin6  result fine ---- CRITICAL: altered for /usr/bin/bin7

I just need to output the following with sed/awk operation on file

Code:
---- CRITICAL: altered for /usr/bin/bin1  ---- CRITICAL: altered for /usr/bin/bin4  ---- CRITICAL: altered for /usr/bin/bin7

# 2  
Old 03-04-2013
Code:
sed 's/OK: [^-]* ---- //g' file

This User Gave Thanks to balajesuri For This Post:
anil510
# 3  
Old 03-04-2013
balajesuri,

here the issue is that, if the last result contain OK, it fails
Code:
root@server [/] echo "---- OK: /usr/sbin/bin3 result fine ---- CRITICAL: altered for /usr/bin/bin4 ---- OK: /usr/bin/bin5 result fine " | sed 's/OK: [^-]* ---- //g'
---- CRITICAL: altered for /usr/bin/bin4 ---- OK: /usr/bin/bin5 result fine

Just CRITICAL values should be printed.
# 4  
Old 03-04-2013
Try:
Code:
sed 's/---- OK: [^-]*//g' file

# 5  
Old 03-04-2013
Using awk
Code:
awk ' BEGIN {
        f = 1
} {
        for ( i = 1; i <= NF; i++)
        {
                if ( $i ~ /CRITICAL:/ )
                {
                        f = 1
                }
                if ( $i ~ /OK:/ )
                {
                        f = 0
                }
                if ( f == 1 )
                {
                        printf "%s ", $i
                }
        }
        printf "\n"
} ' file

This User Gave Thanks to Yoda For This Post:
anil510
# 6  
Old 03-04-2013
bipinajth

It worked flawlessly. Thanks Smilie
# 7  
Old 03-04-2013
Code:
awk -F"---- " '{for (i=2;i<=NF;i++) {if ($i~"^CRITICAL:") {printf "---- %s", $i}}{print ""}}' file

Code:
---- CRITICAL: altered for /usr/bin/bin1 ---- CRITICAL: altered for /usr/bin/bin4 ---- CRITICAL: altered for /usr/bin/bin7
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