Specify an entire UNIX command as a command line argument

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# 1  
Old 02-18-2013
Specify an entire UNIX command as a command line argument

I'm trying to write a bash script called YN that looks like the following

YN "Specify a question" "doThis" "doThat"

where "doThis" will be executed if the answer is "y", otherwise "doThat".

For example

YN "Do you want to list the file dog?" "ls -al dog"  ""

Here's my attempt at the script YN

echo "$1"
read Answer;
if [ "$Answer" = "y" ] ; then
    . "$2"
    . "$3"

If I run the above example it returns

ls -al dog: No such file or directory

Could anybody advise please?
# 2  
Old 02-19-2013
Try this code


echo -n $1


if [ "$ANSWER" = "y" -o "$ANSWER" = "Y" ]

you can try executing it in ,
YN "Do you want to list the file dog?" "ls -al dog" ""

The file dog should be in current directory, or else mention the path.
Thanku Smilie
# 3  
Old 02-19-2013
Note that things like variables, wildcards, and backticks won't be expanded inside the command. This is a security feature to prevent people from doing horrible things just by accidentally misusing a variable.
# 4  
Old 02-20-2013
Why not try something like this for you YN script:

while [ -z "$ans" ]
    printf "%s" "$1"
    read ans
    case $ans in
        y|Y) true;;
        n|N) false;;
        *)   tput cuu1

You can then use the if statement to deal with both answers.
Note you can also nest questions and it all looks pretty neat:

if YN "Do you want to list the file dog? "
    ls -al dog
    if YN "How about the file cat then? "
        ls -al cat

---------- Post updated 21-02-13 at 06:25 AM ---------- Previous update was 20-02-13 at 06:56 AM ----------

Also, if you have a single action you can combine use && like this:

YN "Do you want to list the file dog? " && ls -al dog

or use || if action is for negative response.
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