Help with Backup Shell Script


 
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# 1  
Old 02-06-2013
Help with Backup Shell Script

i need to print the first date of the previous month in 20130101 format.

i use the below script
Code:
month_year=$(date +'%m%Y' | awk '!--$1{$1=12;$2--}')
m=${month_year% *}
y=$month_year##* }
d=$(cal $m $y | paste -s - | awk '{print $NF}')
firstdate=${printf '02d01%s' $y $m)
echo $firstdate

it print as "2013101"

any one can help me on this to print 20130101 as yyyymmdd format

---------- Post updated at 08:57 AM ---------- Previous update was at 08:56 AM ----------

thanks in advance

---------- Post updated at 09:36 AM ---------- Previous update was at 08:57 AM ----------

i m using

Code:
month_year=$(date +'%m%Y' | awk '!--$1{$1=12;$2--}')
m=${month_year% *}
y=$month_year##* }
d=$(cal $m $y | paste -s - | awk '{print $NF}')
firstdate=${printf '%s01%02d' $y $m)
echo $firstdate


the output is as 20130101


i m getting the correct o/p
thanks

Last edited by Franklin52; 02-06-2013 at 11:44 AM.. Reason: Please use code tags for data and code samples
# 2  
Old 02-06-2013
In this way I get the first day in the previous month:
Code:
date +"%Y %m"| awk '{ printf "%4d%02d01\n", ($2 == 1)?$1-1:$1,($2 == 1)?12:$2 - 1;}'

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