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Print the complete line based on position as input

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# 1  
Old 02-06-2013
Print the complete line based on position as input
Hi ,

I have a text file like below

Code:
abcd2223232321212121324343
asdsfffhfgfgfhgfhghghghghghgh
dfdfdfgfghfgfgfgfgfgghghghghgh
dfdfdfdfdfdfdfdfdfdfdfdfdfdfdfdf
1234567890sasasasfdfbffghffhf
abcd222323232121212abcdsds

in the above file i need to grep and print the lines if 14th to 18th character = 1212

The output should be the complete line like below

Output :

Code:
abcd2223232321212121324343
abcd222323232121212abcdsds

some one please help
Last edited by Scrutinizer; 02-06-2013 at 08:05 AM.. Reason: code tags
# 2  
Old 02-06-2013
What have you tried so far?
# 3  
Old 02-06-2013
I tried the following

Code:
cut -b14-18 input > input1
egrep -finput1 input > output.

In this i am getting all the lines that contain the character 1212 also.
Last edited by Scrutinizer; 02-06-2013 at 08:15 AM.. Reason: code tags
# 4  
Old 02-06-2013
Try:
Code:
awk 'substr($0,14,4)==1212' file

# 5  
Old 02-06-2013
Thanks man it worked awesome Smilie and nawk also worked out
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