awk count fields not working


 
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# 1  
Old 02-02-2013
awk count fields not working

Hi,

i am trying to count the fields in a file.
Input:
Code:
100,1000,,2000,3000,10/26/2012 12:12:30
200,3000,,1000,01/28/2012 17:12:30
300,5000,,5000,7000,09/06/2012 16:12:30

output:
Cout of the fileds for each row
Code:
6
5
6

Code:
awk -F"," '{print $NF}' file1.txt

When i try with above awk command i am getting the below output and it is not working as expected.
Code:
12:12:30
17:12:30
16:12:30

Any suggestion using awk command for couting the fields.

Last edited by Scott; 02-02-2013 at 04:54 AM.. Reason: More code tags
# 2  
Old 02-02-2013
Use NF instead of $NF.

But your output with $NF is strange, given the field separator you've used.
# 3  
Old 02-02-2013
thanks for swift responce.
i can find the total fileds in the row which is not equal to 6
Code:
awk -F"," '{print NF","$0}' |grep -v "^6"

Input
Code:
100,1000,,2000,3000,10/26/2012 12:12:30
200,3000,,1000,01/28/2012 17:12:30
300,5000,,5000,7000,09/06/2012 16:12:30

Output
Code:
5,200,3000,,1000,01/28/2012 17:12:30

i unable to print the only values not include the count
Code:
required output : fileds not having 6 and print only values and not include 
200,3000,,1000,01/28/2012 17:12:30

i want to print only data not count in the output.

Last edited by Scott; 02-02-2013 at 02:34 PM.. Reason: As RudiC suggest, please use code tags for code and data
# 4  
Old 02-02-2013
Please use code tags for data as well!
Try
Code:
awk -F"," 'NF!=6'
200,3000,,1000,01/28/2012 17:12:30

No need for grep. awk will check the field count, and, if eq. 6, print the line, otherwise, not.
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