Shell Programming and Scripting

awk '{ if ($5>80) && if ($5 != 100) print $0}

>bdf1|sed 's/%//g'|awk '{ if ($5>80) && if ($5 != 100) print $0}'
 syntax error The source line is 1.
 The error context is
                { if ($5>80) >>>  && <<< 
 awk: The statement cannot be correctly parsed.
 The source line is 1.

[root@host ~]# echo "a a a a 80 a" | awk '( $5 > 80 ) && ( $5 != 100 ) { print $0 }'
[root@host ~]# echo "a a a a 99 a" | awk '( $5 > 80 ) && ( $5 != 100 ) { print $0 }'
a a a a 99 a
[root@host ~]# echo "a a a a 100 a" | awk '( $5 > 80 ) && ( $5 != 100 ) { print $0 }'
[root@host ~]# echo "a a a a 101 a" | awk '( $5 > 80 ) && ( $5 != 100 ) { print $0 }'
a a a a 101 a

awk '$5>80&&$5!=100{print $0}' filename

awk '{if(($5>80)&&($5!=100)) print $0 } ' filename

awk '$5>80&&$5!=100' filename

awk '$5>80&&$5!=100' filename

awk '( $5 > 80 ) && ( $5 != 100 ) { print $0 }' filename