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Using awk to determine if field value is valid

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# 1  
Old 01-25-2013
Using awk to determine if field value is valid
Hi Forum.

I tried to search the forum posts for an answer but I haven't been able to do so for what I'm trying to accomplish.

I have the following source file:
Code:
11936385~TFSA|11936385|4431|3401458067|10/09/1982|25.00|IBSBONUS|3200|||||CASH|
3401458067|1005|
21936385~TFSA|11936385|4431|3401458067|10/09/1982|0|IBSBONUS|3200|||||CASH|3401
458067|1005|
31936385~TFSA|11936385|4431|3401458067|10/09/1982|A|IBSBONUS|3200|||||CASH|3401
458067|1005|
41936385~TFSA|11936385|4431|3401458067|10/09/1982||IBSBONUS|3200|||||CASH|34014
58067|1005|

Field#6 has to be a dollar amount or count value greater than zero. So for this example, first record is valid while the last 3 records are not valid.

This is the code that I have so far but it's not returning the correct expected results:
Code:
awk -F"|" '$6=="" || $6=="0" || $6 !~ /^[0-9]*.[0-9]*$/ {print $0}' filename

Thanks for your help.
# 2  
Old 01-25-2013
Try:
Code:
awk -F\| '$6+0>0' file

This User Gave Thanks to Scrutinizer For This Post:
pchang
# 3  
Old 01-25-2013
Gee - that was just a simple but elegant solution. Smilie
# 4  
Old 01-25-2013
It could be shortened still: Smilie
Code:
awk -F\| '$6+0' file

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