Extract a string from a file and store it in variable


 
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# 1  
Old 01-24-2013
Extract a string from a file and store it in variable

Hi,

I've a file ImageSizeDetails.txt with the following contents:

Code:
Image Name:   swncd 01.10.00.04
Created:      Wed Jan  9 14:05:48 2013
Image Type:   ARM Linux Multi-File Image (gzip compressed)
Data Size:    7351011 Bytes = 7178.72 kB = 7.01 MB
Load Address: 00008000
Entry Point:  00008000
Contents:
   Image 0: 1672879 Bytes = 1633.67 kB = 1.60 MB
   Image 1: 5678119 Bytes = 5545.04 kB = 5.42 MB

I need to extract the size of Image 0 in bytes (i.e) 1672879 alone& save it in a variable. Kindly help me with a shell script

Last edited by Scrutinizer; 01-24-2013 at 05:54 AM.. Reason: code tags
# 2  
Old 01-24-2013
One way:

Code:
isiz=$(awk '/Image 0/{print $3}' file)

Guru
# 3  
Old 01-24-2013
Pls use code tags as advised!
You may want to learn awk, as it is a very powerful tool for requirements like your. For a starting help, try
Code:
$ var=$(awk '/Image 0/{print $3}' file); echo $var
1672879

# 4  
Old 01-24-2013
Thank you, so much
# 5  
Old 01-24-2013
Hi

Also you can try following two codes

Code:
grep -w "Image 0" ImageSizeDetails.txt|awk '{print $3}'

Code:
grep -w "Image 0" ImageSizeDetails.txt|cut -d " " -f3


Last edited by Scrutinizer; 01-24-2013 at 06:05 AM.. Reason: ICODE tags changed to CODE tags; again: ICODE tags changed to CODE tags
# 6  
Old 01-24-2013
Quote:
Originally Posted by sdebasis
Hi

Also you can try following two codes

Code:
grep -w "Image 0" ImageSizeDetails.txt|awk '{print $3}'

grep -w "Image 0" ImageSizeDetails.txt|cut -d " " -f3
i dont think, second grep command will work.

Code:
 
$ cat a.txt
   Image 0: 1672879 Bytes = 1633.67 kB = 1.60 MB
$ grep -w "Image 0" a.txt | cut -d " " -f3
 
$ grep -w "Image 0" a.txt | cut -d " " -f5
0:
 
$ grep -w "Image 0" a.txt | cut -d " " -f6
1672879

# 7  
Old 01-24-2013
Hi Kamaraj,

It was my mistake.
You are right......Smilie
It should be

grep -w "Image 0" a.txt | cut -d " " -f6
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