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awk - output comming strange: for operator ~ and == .

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# 1  
Old 01-17-2013
awk - output comming strange: for operator ~ and == .
Hi awk experts,

I am getting a strange output , may be it is normal but I am unable to comprehend,

When Using == operator it is showing correct:
Code:
# ls -l | awk '{for (i=0;i<=NF;i++) if ( $i =="info" )print $1,$6,$7,$8,$9}'
drwx------ Jan 17 10:44 info




But When using ~ (equal ) operator: two line output comes, when data has only one line only:

Code:
# ls -l | awk '{for (i=0;i<=NF;i++) if ( $i ~ "info" )print $1,$6,$7,$8,$9}'
drwx------ Jan 17 10:44 info
drwx------ Jan 17 10:44 info


Can you guys please explain, whats wrong happening here,
Thank you,
# 2  
Old 01-17-2013
start loop at i=1
This User Gave Thanks to rdrtx1 For This Post:
rveri
# 3  
Old 01-17-2013
Try:
Code:
ls -l | awk '{for (i=1;i<=NF;i++) if ( $i ~ "info" )print $1,$6,$7,$8,$9}'

This User Gave Thanks to Scrutinizer For This Post:
rveri
# 4  
Old 01-17-2013
awk != perl - arrays start indexing with 1 (not 0):
Code:
for (i=1;i<=NF;i++)

You can probably figure out what happens when you do pattern matching with $0
This User Gave Thanks to vgersh99 For This Post:
rveri
# 5  
Old 01-18-2013
rdrtx1 , Scrutinizer , vgresh99 Thank you , I got it , loop should be started with 1, thanks a lot.
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