If conditions in awk


 
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# 1  
Old 01-17-2013
If conditions in awk

Hello Friends,

I need to find some CDRs in production servers whose 1st field value and 2nd field value = 1 and 11th looks like 45.123... where there are more than 3 digits after comma.so i wrote a one liner, something like below but does not work, however when i used first and second conditions it worked:

Code:
for file in `find . -type f -name "*.txt" -mtime -30 2>/dev/null`; do nawk -F\| '{if (($1==1) && ($2==1) && ($11~[0-9]*\.[0-9][0-9][0-9]*)) print $0}' $file; done

Code:
nawk: syntax error at source line 1
 context is
        {if (($1==1) && ($2==1) && >>>  ($11~[ <<< 
nawk: illegal statement at source line 1

Any suggestions, corrections welcome.

I couldnt find any other way to achieve this rather than awk..

Thanks in advance,
my best regards
# 2  
Old 01-17-2013
Hi.

~ is expecting a regular expression, which should be between /.../

Code:
[root@wiki ~]# echo 123 | awk '$1 ~ /.[0-9]./'
123
[root@wiki ~]# echo abc | awk '$1 ~ /.[0-9]./'
[root@wiki ~]#

# 3  
Old 01-17-2013
Quote:
Originally Posted by Scott
~ is expecting a regular expression, which should be between /.../

Code:
[root@wiki ~]# echo 123 | awk '$1 ~ /.[0-9]./'
123
[root@wiki ~]# echo abc | awk '$1 ~ /.[0-9]./'
[root@wiki ~]#

I have just realised this and tried q min ago, but it didnt give me correct output:


Code:
nawk -F\| '{if ((($1==1) && ($2==1)) && ($11~/[0-9]*\.[0-9][0-9][0-9]*/)) print $0}' $file

in output the 11th field has all values like 12.34 rather than 12.345.....
Code:
1|1|1|sscmws-5400609|9840001131523171327|||20130113152317|scr|ccn-r|7.83|||3|784|3|7.83|971507857285|0|360||2|||CCN1|0
1|1|1|sscmws-5400611|9840001131524001329|||20130113152400|scr|ccn-r|5.48|||3|784|3|5.48|971509420582|0|360||2|||CCN1|0
.
.

should i put one more [0-9] ?? Smilie
# 4  
Old 01-17-2013
Replace the * with a +. Try:
Code:
awk -F\| '$1==1 && $2==1 && $11~/\.[0-9][0-9][0-9]+/' infile "$file"

or
Code:
awk -F\| '$1==1 && $2==1 && $11~/\.[0-9]{3,}/' infile

The latter will not work with mawk and needs the --posix option with gawk (if <4.0)
This User Gave Thanks to Scrutinizer For This Post:
# 5  
Old 01-17-2013
Quote:
Originally Posted by Scrutinizer
[...]
Code:
awk -F\| '$1==1 && $2==1 && $11~/\.[0-9]{3,}/' infile

The latter will not work with mawk and needs the --posix option with gawk (if <4.0)
Or use --re-interval, if you want to enable just that feature and if you don't want to disable all GNU awk extensions and those not allowed by POSIX.
This User Gave Thanks to radoulov For This Post:
# 6  
Old 01-17-2013
Quote:
Originally Posted by Scrutinizer
Replace the * with a +. Try:
Code:
awk -F\| '$1==1 && $2==1 && $11~/\.[0-9][0-9][0-9]+/' infile "$file"

or
Code:
awk -F\| '$1==1 && $2==1 && $11~/\.[0-9]{3,}/' infile

The latter will not work with mawk and needs the --posix option with gawk (if <4.0)
Thanks Scrutinizer as you remind me how to use combinations of {3} ..

I need something else, on another directory form of some warning CDRs is a bit different, the last field so i need to check sub fields of last field of CDRs and print them,
Code:
here a sample of CDR:
1|1|1|sscmws-5400746|9840001141031191292|||20130114103119|scr|ccn-r|43.98||ratedPrice and chargedAmount are different. rp:43.98 ca:43.980000000000004

i tried this but didnt work:

Code:
for file in `find . -type f -name "*.txt" -mtime -30 2>/dev/null`; 
do nawk -F\| '{split($NF,arr,":"); if ((arr[2+0]~/\.[0-9]{3,}/) || (arr[3]~/\.[0-9]{3,}/)) print $0}' $file; 
done

I could not parse only numerical part of second array adding "+0" and so i cant check second arrays which is "43.98" in sample,
# 7  
Old 01-17-2013
Code:
for file in `find . -type f -name "*.txt" -mtime -30 2>/dev/null`
do 
  nawk -F\| '$NF ~ /.*:[0-9][0-9]*[.][0-9][0-9]$/'' $file
done

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