Shell script - entered input(1-40 bytes) needs to be converted exactly 40 bytes


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# 1  
Shell script - entered input(1-40 bytes) needs to be converted exactly 40 bytes

hello,

suppose, entered input is of 1-40 bytes, i need it to be converted to 40 bytes exactly.

example: if i have entered my name anywhere between 1-40 i want it to be stored with 40 bytes exactly.

enter your name:
donald duck (this is of 11 bytes)

expected is as below - display 11 bytes entered and rest of the 29 bytes with blank space
donald duck____________________________(i refereed _ to blank space)


my shell script is something like below:
Code:
echo "enter you name"
read name
echo "enter age"
read age
echo $name$age


please help!

Last edited by Franklin52; 01-17-2013 at 04:11 AM.. Reason: Please use code tags for data and code samples
# 2  
printf?
Code:
printf "%-40s" "Donald Duck"

This User Gave Thanks to balajesuri For This Post:
# 3  
You do not mention the shell that you are using. In bash, the following would give the desired result:
Code:
$ read
$ printf -v name "%40s" "$REPLY"
$ echo "$name":
                             Donald Duck:

Use -40 for left justified text.
# 4  
Thanks... it works.

i have another question - let's suppose i enter 41 chars, but i want first 40 chars to be read. can this be possible? please let me know.

echo "enter your name"
read name
printf "%-40s" "$name" (gives me 40 bytes) but here if i entered more than 40 chars it displays them all, but i need only first 40 chars.
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