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Passing a variable as input to another shell

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# 1  
Old 12-12-2012
Passing a variable as input to another shell
I have a shell program that calls another shell program

the following code works
Code:
. chkTimeFormat.sh "10/9/12 17:51:19:783."|read c

but when I am passing the the time in a variable like in the code below, the shell chkTimeFormat.sh is not returning proper value

Code:
time="10/9/12 17:51:19:783."
. chkTimeFormat.sh $time|read c

Please help
# 2  
Old 12-12-2012
Try using double quotes..

Code:
. chkTimeFormat.sh "$time"|read c

# 3  
Old 12-12-2012
Thanks but ,
Code:
. chkTimeFormat.sh "$time"|read c

it did not work.
Any more ideas...
Last edited by Franklin52; 12-12-2012 at 04:01 AM.. Reason: Please use code tags for data and code samples
# 4  
Old 12-12-2012
What does not work? Pls be more specific, post output and/or error samples, variable contents, etc.
# 5  
Old 12-12-2012
Quote:
Originally Posted by swayam123
Thanks but ,
Code:
. chkTimeFormat.sh "$time"|read c

it did not work.
Any more ideas...
As Rudic said Please provide some details..

Please look how double quotes makes difference here.. Smilie

Code:
$ cat test2.sh
echo $1

$ . test2.sh "10/9/12 17:51:19:783."
10/9/12 17:51:19:783.

$ time="10/9/12 17:51:19:783."

$  . test2.sh $time
10/9/12

$ . test2.sh "$time"
10/9/12 17:51:19:783.

Hope this helps

pamu
# 6  
Old 12-12-2012
This the code for chkTimeFormat.sh is as follows
Code:
time=$1
var=$(echo "$time"|awk '{for(i=1;i<=NF;i++) if ( $i ~  /[0-2][0-9]:[0-5][0-9]:[0-5][0-9]/){print i}} ')

if [ $var -ge 0 ] 
then
 echo 1
else
 echo 0

fi

I called this script as follows from a different script n the following way
Code:
time="10/9/12 17:51:19:783."
. chkTimeFormat.sh $time|read c
echo $c

and

Code:
time="10/9/12 17:51:19:783."
. chkTimeFormat.sh "$time"|read c
echo $c

I was expecting and output
1
but I am getting
0

Please suggest
# 7  
Old 12-12-2012
Code:
 
c=$(. chkTimeFormat.sh "$time")
echo $c
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