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Top Forums Shell Programming and Scripting Get the list with sed or awk

12-05-2012

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Quote:

Originally Posted by yanglei_fage

I understand it partly, if change zzz D to a variable, can we get it eg: VAR="zzz D"

I am not clear what you are saying..

As per your requirement code prints lines after if it finds [General] or [zzz D].

Here i just use a for printing the expected result.

Quote:

Originally Posted by michaelrozar17

Through Sed..

Code:

$ sed -n 'H;${
x
s/[^]]*]\n\([^[]*\).*\[zzz D\]\n\([^[]*\)\n.*/\1\2/p
}' inputfile

This will fail if it file starts with any other tags than [General].

And if you are saying as you want to pass variable as Jotne pointed out then use.

Code:

awk -v var="[zzz D]" '/^\[/{a=""}
a{print}
/\[General\]/ || $0 == var{a=1}' file

Quote:

Originally Posted by Jotne

Code:

awk '/^\[/{a=""}
a{print}
$0~"[General]" || $0~var {a=1}' var="[zzz D]" file

Edit: This gives to much, not sure whats wrong

@Jotne -
you can do like /\[General\]/ || $0 == var

Last edited by pamu; 12-05-2012 at 02:33 AM..

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