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Unable to convert passwd lastupdate value into scalar local format

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# 1  
Old 11-21-2012
Unable to convert passwd lastupdate value into scalar local format
Dear all,

I am unable to get the desired result upon executing the below script. the problem is at `perl -le 'print scalar localtime $msecage'` ouput which gives the following result "Thu Jan 1 05:00:00 1970" instead of "Tue Nov 13 10:30:56 2012" but when I run the same command from shell prompt by putting the actual value infront of perl localtime perl -le 'print scalar localtime 1352784656 it gives the correct result.

Please help



Code:
#!/usr/bin/ksh

################# This script will print the User Password Max Age, Last Change, Calculate Passwd expiry#####

mxage=`sudo lsuser -a maxage ahd11542|awk -F= '{print $2}'` 

mxlastupdate=`sudo lssec -f /etc/security/passwd -a lastupdate -s ahd11542 |awk '{print $2}'|cut -b 12-`

msec=` expr 604800 \* $mxlastupdate`

msecage=`expr $msec + $mxlastupdate`

expiredate=`perl -le 'print scalar localtime $msecage'`


#############DISPLAY OUTPUT#################

echo "Max age is:" $mxage

echo "Last Change is:" $mxlastupdate

echo "Last Change in localtime is:" `perl -le 'print scalar localtime $mxlastupdate'`

echo "Max Age in Seconds:" $msecage

echo " Expiration Date is:"$expiredate

# 2  
Old 11-21-2012
Hi

mxlastupdate is a shell variable which you are trying to access in Perl directly which will not work.

Code:
export mxlastupdate
echo "Last Change in localtime is:" `perl -le 'print scalar localtime $ENV{'mxlastupdate'}'`

Export the variable in shell, and use the ENV hash in perl to access the env variable.


Guru.
This User Gave Thanks to guruprasadpr For This Post:
m_raheelahmed
# 3  
Old 11-21-2012
use double quotes

Code:
echo "Last Change in localtime is:" `perl -le "print scalar localtime $mxlastupdate"`

This User Gave Thanks to itkamaraj For This Post:
m_raheelahmed
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