Range of number from 0.1 to 10.0


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# 1  
Linux Range of number from 0.1 to 10.0

Is there a way to create a loop that will output number starting from 0.1 to 10.0
0.1
0.2
0.3
0.4
0.5
..
...
10.0

This is what i tried.
Code:
for i in {1..50}; do     printf -v i '%02d' $i ;     echo "$i"; done

That will print
01
02
03
..
..
50

How do i add a period in between the two numbers?
# 2  
Try:
Code:
for i in {1..50}; do printf -v i '%0.1f' `echo "scale=1;$i/10" | bc`; echo $i; done

# 3  
Quote:
Originally Posted by bartus11
Try:
Code:
for i in {1..50}; do printf -v i '%0.1f' `echo "scale=1;$i/10" | bc`; echo $i; done

Thanks you! Its work.
# 4  
Code:
#!/bin/bash
for i in {0..10}; do
        for j in {0..9};  do
                echo $i"."$j
        done
done

---------- Post updated at 21:28 ---------- Previous update was at 20:45 ----------

Code:
#!/bin/sh
awk 'BEGIN { for(i=0;i<=10;i++) for(j=0;j<=9;j++) print i "." j }' | awk '!/0.0/'

Edit: removed the first 0.0, starting from 0.1 to 10.0 as requested.

Last edited by Jotne; 11-17-2012 at 06:27 PM..
# 5  
Code:
man seq

Code:
$ seq -f %02.1f 0.1 0.1 10

Code:
$ seq -f %02.1f 0.1 0.1 10 | nawk 'NR<8||NR>92{print;next}!c++{print "..."}'
0,1
0,2
0,3
0,4
0,5
0,6
0,7
...
9,3
9,4
9,5
9,6
9,7
9,8
9,9
10,0
$


Last edited by ctsgnb; 11-17-2012 at 06:58 PM..
# 6  
Code:
echo 1 10 | awk ' { for (i=$1; i<=$NF; i++) printf("%.1f\n", i/10); } '
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1.0

# 7  
or just use ksh93:
Code:
$ for ((i=.1;i<=10;i+=.1)); do printf "%.1f\n" $i; done
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1.0
...
9.9
10.0

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