Getting value of a pattern preceding another pattern

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# 1  
Getting value of a pattern preceding another pattern

I have a file like this
[2012-11-12 :  11:59
 some text
 some moe text
soe more text
[2012-11-12 : 12:00 blala blah blah]
[2012-11-12 :  12:01
 some text
 some moe text
soe more text
[2012-11-12: 12:02  some other text ]


I need a way to find the timestamp preceding the ERR-XXXXX

Here XXXX deonoes any any numeric string 00000-99999
that is a output like this

2012-11-12 :  11:59-ERR-XXXXX
2012-11-12 :  12:01-ERR-XXXXX

Last edited by Scrutinizer; 11-16-2012 at 06:49 AM.. Reason: code tags
# 2  
awk '/\[2012/{a=$0}/^ERR/{print a"-"$0}' input.txt
[2012-11-12 : 11:59-ERR-XXXXX
[2012-11-12 : 12:01-ERR-XXXXX

---------- Post updated at 10:01 AM ---------- Previous update was at 09:59 AM ----------

awk '/\[2012/{sub("\\[","",$0);a=$0}/^ERR/{print a"-"$0}' input.txt
2012-11-12 : 11:59-ERR-XXXXX
2012-11-12 : 12:01-ERR-XXXXX

This User Gave Thanks to itkamaraj For This Post:
# 3  
the command is working in the shell.
However when calling this same command from a function
$0 is getting replaced by KSH and the date part is not coming only ERR part is coming

like this
-ERR-XXXXX some more text
-ERR-XXXXX some other text

Last edited by Scrutinizer; 11-16-2012 at 06:59 AM.. Reason: code tags
# 4  
can you show your function and how you are calling the function?
# 5  
echo "In Function ...processing $1"

echo "awk '/\[$1/{sub("\\[","",$0);a=$0}/^ORA/{print a"-"$0}'" 
awk '/\[$1/{sub("\\[","",$0);a=$0}/^ERR/{print a"-"$0}' $2.log>>$3 

awk '/\[$1/{sub("\\[","",$0);a=$0}/^ERR/{print a"-"$0}' $2_$4>>$3 

awk '/\[$1/{sub("\\[",""$0);a=$0}/^ERR/{print a"-"$0}' $2_$5>>$3 

myFunc "$currentMonth\/$currentDay\/$currentYearYY" SystemOut $inputFile "$currentYearYY.$currentMonth0.$currentDay0*"  $prevDayYr.$prevDayMonth.$prevDayDay

Last edited by Scrutinizer; 11-16-2012 at 06:50 AM.. Reason: code tags
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