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awk - treating remaining columns as one

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# 29  
Old 11-17-2012
or sed
Code:
sed 's!\([^ \t]*\)[ \t]\{1,\}\([^ \t]*\)[ \t]\{1,\}\(.*\)!\1\n\2\n\3!g' file

# 30  
Old 11-17-2012
Quote:
Originally Posted by only4satish
lets say if i have file as below
Code:
 
cat sample.txt
satish
/rakesh/
sandhya
/sandeep/

i have to replace /rakesh/ with rakesh, how can i do it with sed, i tried below code but its throwing errors

Code:
 
sed -e 's/'"\(/rakesh/)\"'/\1rakesh/g' sample.txt

please help me.............
You aren't quoting the separator character correctly in this case where some of the characters you're trying to match are separator characters. When you need to look for and replace a / character, use something else as the separator, such as:
Code:
 
sed -e 's|/rakesh/|rakesh|g' sample.txt

If for some reason you really need to keep / as your separator, the following will also work:
Code:
 
sed -e 's/\/rakesh\//rakesh/g' sample.txt

This User Gave Thanks to Don Cragun For This Post:
only4satish
# 31  
Old 11-17-2012
@bala

Code:
cat t1
 
CMF_COM_ELEMENT_log   68715079 rows inserted into ALL_S1_CMF_COM_ELEMENT.
CMF_COM_ELEMENT1_log   68715 rows inserted into ALL_S1_CMF_COM_ELEMENT1.
CMF_COM_ELEMENT2_log   68715 rows inserted into ALL_S1_CMF_COM_ELEMENT2.

expedted output :
Code:
CMF_COM_ELEMENT 68715079 
CMF_COM_ELEMENT1 68715 
CMF_COM_ELEMENT2 68715

Code:
 

awk '{sub("_log","",$1); print $1,$2}'  t1

how the below code works ?? can u please let me know sub logic ???
Code:
 
 
sub("_log","",$1);

Last edited by Scrutinizer; 11-17-2012 at 07:00 AM.. Reason: code tags
# 32  
Old 11-17-2012
Assuming the rest of your file have the same formatting than the lines of your example:

Code:
sed 's:/rakesh/:rakesh:' input

or

Code:
sed '/rakesh/s:/::g' input

This User Gave Thanks to ctsgnb For This Post:
only4satish
# 33  
Old 11-17-2012
Quote:
Originally Posted by only4satish
@bala
... ... ...
Code:
awk '{sub("_log","",$1); print $1,$2}'  t1

how the below code works ?? can u please let me know sub logic ???
Code:
sub("_log","",$1);

Search for _log in $1 and if found change it to an empty string. In other words if the first field in the input record contains _log, remove those four characters from that field.
This User Gave Thanks to Don Cragun For This Post:
only4satish
# 34  
Old 11-17-2012
@Don , thanks a ton
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