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Simple sed script question

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# 1  
Old 11-09-2012
Simple sed script question
Script newbie, so I'm sure I'm missing something obvious here, but how come this simple script does not work?

Code:
#!/bin/bash                                                                                                                                                                                                                                      
sed '/$1/,/^$/!d' $2

I make the script executable and run ./script.sh string filename, but nothing happens and I any result at all, even though this works fine in the shell:

Code:
sed '/string/,/^$/!d' filename

# 2  
Old 11-09-2012
use double-quotes instead of the single-quotes - you need to have your script parameter evaluated.
This User Gave Thanks to vgersh99 For This Post:
KidCactus
# 3  
Old 11-09-2012
Thank you for the quick reply, and yes, that did the trick. Much appreciated. Smilie

---------- Post updated at 06:33 PM ---------- Previous update was at 06:00 PM ----------

And if I want to be able to input multiple filenames? This apparently doesn't work the way I expected:

Code:
#!/bin/bash                                                                                                                                                                                                                                      
for i
do
sed "/$1/,/^$/!d" $2
done

./script.sh string filename*

I have 3 files with the name filename1, filename2 and filename3, but my script only returns the result from filename1, and does it three times. I'm lost...
Last edited by KidCactus; 11-09-2012 at 02:07 PM..
# 4  
Old 11-10-2012
Try:
Code:
#!/bin/bash
str=$1
shift
for i
do
 sed '/'"$str"'/,/^$/!d' "$i"
done

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