Simple awk question


 
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# 1  
Old 10-22-2012
Simple awk question

Hi All,
A very silly question:
How to just print the integer attached a particular string in a line by awk?
Ex:
Happy_world_foo123...So i just want the value 123 to be printed on the line where we have string "foo".
Thanks
# 2  
Old 10-22-2012
What have you tried so far? Must it be awk and when why?
Answers that show up before the OP answers will be moderated. Thanks for your understanding!
# 3  
Old 10-22-2012
Hi Help!!
I have been searching through a particular value that need to be printed separately.
Suppose,
Happy_world_foo-123.
So to search a string with foo and just to print the value 123,on a line from a text file.
Do anyone have any idea.
Thanks
# 4  
Old 10-22-2012
Code:
awk -F"-" '/foo/ {print$2}' /tmp/yourfile

You did change the line in your two example, so not sure how to trigger to get the value. (change from foo123 to foo-123)
# 5  
Old 10-22-2012
Hi Jotne,
It is Just foo123.
So a line with Happy_world_foo123.I just want 123 to be printed when we have string foo in a line.
Thanks
# 6  
Old 10-22-2012
Code:
echo "Happy_world_foo123" | awk -F"foo" '/foo/ {print$2}'

This search for all line with foo and prints all after it.
If you have other characters after number or more than one foo in same line, this does not work.
# 7  
Old 10-22-2012
A hint:
Code:
var='Happy_world_foo123'

echo ${var#*foo}
123

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