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Bash script - $(ls expr) return double file name with one finishing with '.'

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# 1  
Old 10-20-2012
Bash script - $(ls expr) return double file name with one finishing with '.'
Hello.

This small part of my script

Code:
#!/bin/bash
SRCDIR=/root/.kde4/share/config
for MY_FILE in  $(ls $SRCDIR/kate*) ; do
    echo "$MY_FILE"
done

give :
Quote:
/root/.kde4/share/config/katepartpluginsrc
/root/.kde4/share/config/katepartpluginsrc.
/root/.kde4/share/config/katepartscriptrc
/root/.kde4/share/config/katepartscriptrc.
/root/.kde4/share/config/katerc
/root/.kde4/share/config/katerc.
/root/.kde4/share/config/kateschemarc
/root/.kde4/share/config/kateschemarc.
/root/.kde4/share/config/katesyntaxhighlightingrc
/root/.kde4/share/config/katesyntaxhighlightingrc.
So for the moment I have modified my script like this :
Code:
#!/bin/bash
SRCDIR=/root/.kde4/share/config
for MY_FILE in  $(ls $SRCDIR/kate*) ; do
    if [[ "$MY_FILE" == $SRCDIR/kate* ]] ; then
        if [[ "$MY_FILE" == $SRCDIR/kate*. ]] ; then
            echo .
        else
            echo "Keep this : $MY_FILE"
        fi
    fi
done

which give
Quote:
Keep this : /root/.kde4/share/config/katepartpluginsrc
.
Keep this : /root/.kde4/share/config/katepartscriptrc
.
Keep this : /root/.kde4/share/config/katerc
.
Keep this : /root/.kde4/share/config/kateschemarc
.
Keep this : /root/.kde4/share/config/katesyntaxhighlightingrc
.
But there is surely a best method.
# 2  
Old 10-20-2012
You can remove one if ....Smilie

Code:
#!/bin/bash
SRCDIR=/root/.kde4/share/config
for MY_FILE in  $(ls $SRCDIR/kate*) ; do
    if [[ "$MY_FILE" == $SRCDIR/kate*. ]] ; then
            echo .
        else
            echo "Keep this : $MY_FILE"
        fi    
done

# 3  
Old 10-20-2012
Thank you.
But my question is rather how to prevent $(ls expr) from returning file name with '.' at the end.
# 4  
Old 10-20-2012
Quote:
Originally Posted by jcdole
Thank you.
But my question is rather how to prevent $(ls expr) from returning file name with '.' at the end.
ok try this.. No need to use for loop also...Smilie

Code:
ls $SRCDIR/kate* | grep -v "\.$"

This User Gave Thanks to pamu For This Post:
jcdole
# 5  
Old 10-20-2012
Quote:
Originally Posted by pamu
ok try this.. No need to use for loop also...Smilie

Code:
ls $SRCDIR/kate* | grep -v "\.$"

Great. That do the job.
# 6  
Old 10-21-2012
don't need ls. never use for on ls.

Code:
for file in "$SRCDIR"/kate*; do
    [[ $file = *. ]] && continue
    # ...
done

or use extglob
Code:
shopt -s extglob
for file in "$SRCDIR"/kate!(*.); do
   # ...
done

This User Gave Thanks to neutronscott For This Post:
jcdole
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