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[Solved] Counting specific characters within each field


 
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# 1  
Old 10-19-2012
[Solved] Counting specific characters within each field

Hello,

I have a file like following:
ALB_13554 1 1 1
ALB_13554 1 2 1
ALB_18544 2 0 2
ALB_18544 1 0 1

This is a sample of my file, my real file has 441845 number of fields. What I want to do is to calculate the number of 1 and 2 in each column using AWK, so, the output file looks like this:

3 1 #for the first column which has three 1 and one 2
1 1
3 1

The zeros should be ignored.

Thank you very much for your help in advance.
# 2  
Old 10-19-2012
Code:
awk '{
  for (i=2;i<=NF;i++) {
    n[i,$i]++
  }
}

END {
  for (i=2;i<=NF;i++) {
    print n[i,1] " " n[i,2]
  }
}' file

This User Gave Thanks to delugeag For This Post:
# 3  
Old 10-19-2012
Perfect, thank you very much!
# 4  
Old 10-21-2012
consider I have only "1" in the first field, this script gives me 4 but I want it to give me 0 too as the number of "2". So, to produce an output like this:

4 0

how I can put a condition in the previous script for that?

Thank you very much
# 5  
Old 10-21-2012
With some assumptions (no field has a null/blank value):
Code:
awk '{
for(i=2;i<=NF;i++)
 if($i=="1") c_one[i]++
  else if($i=="2") c_two[i]++}
END{for(i=2;i<=NF;i++) printf("%d\t%d\n",c_one[i],c_two[i])}' file

This User Gave Thanks to elixir_sinari For This Post:
# 6  
Old 10-21-2012
it worked perfectly, thanks a lot!

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