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checking first argument for tag in bash script

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# 1  
Old 10-18-2012
checking first argument for tag in bash script
I have a bash script where I pass an argument

Code:
./chris.bash "\argv Test"


I want to detect if the user supplied \argv at the start of the argument
# 2  
Old 10-18-2012
Code:
 echo "$1" | grep -q "^[\\]argv" || echo Invalid argument

# 3  
Old 10-18-2012
Have tried it in my script but is not printing anything. It works on the command line though.

I came up with

Code:
if [[ "$1" =~ ^[\\]argv* ]]; then
   msg=`echo "$1" | awk 'BEGIN {FS="argv"} {print $2}' | sed 's/^ *//g'`     
   # Removes the "\argv" and any leading spaces     
   echo "$msg"   
fi

# 4  
Old 10-18-2012
Quote:
Originally Posted by kristinu
Code:
if [[ "$1" =~ ^[\\]argv* ]]; then
   msg=`echo "$1" | awk 'BEGIN {FS="argv"} {print $2}' | sed 's/^ *//g'`     
   # Removes the "\argv" and any leading spaces     
   echo "$msg"   
fi

Or, in bash and ksh (and perhaps others) ...
Code:
msg=${1/#\\argv*( )}

Depending on how your bash is configured, you may need to enable extended globbing:
Code:
shopt -s extglob

Regards,
Alister
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