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# 1  
Old 10-16-2012
help with sed
Hello, I have the following file:

Code:
ABCDE_CMS_10.SUNDSVALLALT.I_20120918_120601_P_0296_00.MBF
ABCDE_CMS.1.NOKPART.I_20120918_234811_P_44766_00.MBF
ABCDE_CMS.10.STOF.I_20120919_073742_P_6506.ict.zip
ABCDE_CMSAA.20120918_234810_P_44713_00.MBF
ABCDE_CMS.10.STOF.I_20120919_073742_P_6506.ict.zip
ABCDE_CMS_10.STOF.I.20120919_235242_P_6475_00.MBF
ABCDE_CMS_10.SUNDSVALLALT.I_20120920_120601_P_0296_00.MBF
ABCDE_CM10.STOF.I.20120920_233742_P_6474_00.MBF
ABCDE_CMS.10.STOF.I_20120920_235340_P_6682_00.MBF
ABCDE_CMS10.STOF.I.20120921_233840_P_6681_00.MBF
ABCDE_CMS.1.NOKPART.I_20120920_234811_P_44766_00.MBF
ABCDE_CMS.10.STOF.I_20120921_073742_P_6506.ict.zip
ABCDE_CMSAA.20120921_234810_P_44713_00.MBF

I am using the following command to get all lines that contain dates between 20120919 and 20120921:

Code:
sed -n "/20120919/,/20120921/p" input_file.txt

The problem is that it gets all lines from the first 20120919 to the first 20120921 and when I have 20120918 after 20120919 it also will be included /marked in blue/ and when I have 20120921 before other lines with 20120920 they will be skipped /marked in red/.

Any ideas how can I handle that?

Thanks in advance!
# 2  
Old 10-16-2012
Hi apenkov,

Not an elaborated solution, but could work for this simple case. Try:
Code:
$ sed -n "/201209\(19\|20\|21\)/ p" infile
ABCDE_CMS.10.STOF.I_20120919_073742_P_6506.ict.zip
ABCDE_CMS.10.STOF.I_20120919_073742_P_6506.ict.zip
ABCDE_CMS_10.STOF.I.20120919_235242_P_6475_00.MBF
ABCDE_CMS_10.SUNDSVALLALT.I_20120920_120601_P_0296_00.MBF
ABCDE_CM10.STOF.I.20120920_233742_P_6474_00.MBF
ABCDE_CMS.10.STOF.I_20120920_235340_P_6682_00.MBF
ABCDE_CMS10.STOF.I.20120921_233840_P_6681_00.MBF
ABCDE_CMS.1.NOKPART.I_20120920_234811_P_44766_00.MBF
ABCDE_CMS.10.STOF.I_20120921_073742_P_6506.ict.zip
ABCDE_CMSAA.20120921_234810_P_44713_00.MBF

# 3  
Old 10-16-2012
And, of course, there's grep, which is well suited for this kind of work.

Code:
$ grep -E "20120919|2012092[01]" infile

# 4  
Old 10-16-2012
with awk..

Code:
awk -F "2012" '{s=substr($2,1,4);if( s >= "0919" && s <= "0921" ){print $0}}' file

This User Gave Thanks to pamu For This Post:
apenkov
# 5  
Old 10-16-2012
Hi, the problem is that there can be a lot of dates in the file, let's say for an year ago and start and end date are input from the user.
# 6  
Old 10-16-2012
Code:
awk -v strt=20120919 -v end=20120921 'match($0,/_[0-9]{8}_/){
dt=substr($0,RSTART+1,8)
if(dt+0>=strt+0 && dt+0<=end+0) print}' file

This User Gave Thanks to elixir_sinari For This Post:
apenkov
# 7  
Old 10-16-2012
Quote:
Originally Posted by apenkov
Hi, the problem is that there can be a lot of dates in the file, let's say for an year ago and start and end date are input from the user.
At least for this year it will work..Smilie

Code:
awk -F "2012" -v FM="20120818" -v SM="20120921" '{s="2012"substr($2,1,4);if( s >= FM && s <= SM ){print $0}}' file

This User Gave Thanks to pamu For This Post:
apenkov
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