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Subtracting values from variable

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# 1  
Old 10-12-2012
Subtracting values from variable
Legends,

Please help me in , how do i subtract the variable values listed like below.
the first value of orig should be subtracted from first value of prev and so on.

Code:
san> echo $orig
346 316 340 239 410 107 291 139 128 230 167 147 159 159 172 116 110 260 177 0 177 169 168 186 165 366 195 131 7 143 60 276 149 114 120 110 103 5 0 87 79 104 101 142 184 13 278 2 153 160 0 5 101 127 151 14 196 138 90 177 195 166 135 122 136 117 169 518 244 125 116 127 117 131 129 121 120 164 218 105 111 122 127 123 117 168 536 192 177 133 130 160 78 126 678 277 294 297 842 78

san> echo $prev
346 316 340 239 410 107 291 139 128 230 166 147 159 159 172 116 110 260 177 0 177 167 168 186 165 366 195 131 7 143 60 276 145 114 120 110 103 5 0 87 79 101 99 140 184 13 278 2 153 160 0 5 99 125 150 14 196 136 87 177 195 162 135 121 136 113 169 518 244 125 116 127 117 131 129 119 117 164 218 101 111 122 127 123 116 168 536 192 177 133 130 160 78 126 678 277 294 297 842 78

Pls help
# 2  
Old 10-12-2012
try something like this..

assuming both variables have same number of fields..

Code:
echo "" | awk -v FV="$orig" -v SV="$prev" '{ n=split(FV,F);split(SV,S)}END{
for(i=1;i<=n;i++){printf (S[i] - F[i])" "}}'

I am not able to use just awk..Smilie

any guess?
Last edited by pamu; 10-12-2012 at 10:04 AM..
# 3  
Old 10-12-2012
i Tried the follwoing using array but no go

Code:
for (( i = 0 ; i < ${#orig[@]} ; i++ ))
do
for (( j = 0 ; j < ${#prev[@]} ; j++ ))
do
if [ $i == $j ];
then
(( DIFF = ${orig[i]} - ${prev[j]} ))
echo $DIFF;
else
echo ${orig[i]}  ${prev[j]} > /dev/null 2>&1
fi
done
done

---------- Post updated at 04:51 AM ---------- Previous update was at 04:48 AM ----------

@pamu

below is the error i am gettng

Code:
> echo "" | awk -v FV="$orig" -v SV="$prev" '{ n=split(FV,F);split(SV,S)}END{for(i=1;i<=n;i++){printf (F[i] - S[i])" "}}'
awk: syntax error near line 2
awk: bailing out near line 2

# 4  
Old 10-12-2012
try using nawk
# 5  
Old 10-12-2012
In ksh93/bash (assuming that there are equal number of elements in both variables):
Code:
orig_array=($orig)
prev_array=($prev)
diff=
for((i=0;i<${#orig_array[*]};i++))
do
 diff="$diff $(( ${prev_array[i]} - ${orig_array[i]} ))"
done

echo $diff

producing
Code:
0 0 0 0 0 0 0 0 0 0 -1 0 0 0 0 0 0 0 0 0 0 -2 0 0 0 0 0 0 0 0 0 0 -4 0 0 0 0 0 0 0 0 -3 -2 -2 0 0 0 0 0 0 0 0 -2 -2 -1 0 0 -2 -3 0 0 -4 0 -1 0 -4 0 0 0 0 0 0 0 0 0 -2 -3 0 0 -4 0 0 0 0 -1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

This User Gave Thanks to elixir_sinari For This Post:
sdosanjh
# 6  
Old 10-12-2012
@elixir,
main requirement is: i have two files File A and File B
using these two files, i want out with difference to third one (say file C) after calculating diff from 3rd column from file
using "bash" shell

Code:
file A
abc             xxx  340 
def             yyy  239 
ghi             zzz  410 

file B
abc             xxx  330 
def             yyy  230 
ghi             zzz  310

OUTPUT SHOLUD be
Code:
File C
abc             xxx  10 times diff
def             yyy  9 times diff
so on...

# 7  
Old 10-12-2012
Quote:
Originally Posted by sdosanjh
how do i subtract the variable values listed like below.
Quote:
Originally Posted by sdosanjh
@elixir,
main requirement is: i have two files File A and File B
There is a big difference between how you handle files and variables. You mention variables in one post (and in the thread title) and files in the other.

Please don't try to oversimplify the problem. This makes it difficult to provide a proper solution.
This User Gave Thanks to elixir_sinari For This Post:
pamu
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