Shell Programming and Scripting

Hi,

Please look at below.

This is what i have imagined so far.(this is just base structure we can modify this if it is as per your requirement.)

Please do let me correct if am missing something
All files to while loop are file lists

Code:

while read line
do
#get the XXGoport column number add 5000 and go to next step.
for i in $(awk -F "|" '/XXGoport\|1260\|0\|3871\|0\|/{print $8+5000}' $line)
do
while read line_2
do
#get the XXGflow column number subtract 5000 and go to next step.
for j in $(awk -F "|" -v VM="$line_2" '/XXGflow/ && VM {print $(NF-3)-5000}')  # Choose your column number which column you want to print
while read line_3
do
awk -v IM="$j" '/XXGiport/ && IM' $line_3

done<out_file_iport # files required for get iport number 

done<output_file # files required to get the XXGflow number

done<Input_files    #Input_files is file having list of all input files

Hope this helps you..

For suppose let us assume we have :
now i need


and
As many as i have Input_Files corresponding Input_Files_f files must be generated and they must contain the file names where they had flow(i guess u already got a picture of flow +5000 , -5000) and also for all the Input_Files_f, First line will be the corresponding Input_file name and last line will be Output_File.

Now is it clear??

Okies. But what about middle lines there is no relation to establish between them we can achieve it.

The relation ship b/w middle lines can be achieved by +/-5000 logic.
I am explaining this for u in a simpler way. Assume evry thing i am mentioning below just suppose the numbers but the logic is the same we need to implement.

for suppose:
i/p1 file has O/P numer 1000
join2 has I/P number 5555 , O/P number 1111
reformat3 has I/P number 6666 , O/P number 2222
output has I/P number 7777

1.) Now we need to go like this comming frm i/p1 take 1000
2.) add 5000 which gives 6000
3.) now go to XXGFlow file search for line 6000



4.) So, from the XXGFlow file we will take 10555
5.) Substract 5000, 10555-5000=5555
6.) Go back to files search for 5555 , you will get it in join2 I/P number
7.) search in the same file (join2) for O/P number , u will get 1111
8.) add 5000 , 1111+5000 = 6111
9.) search in XXGFlow for 6111 and u got 11666
10.) substract 5000 , 11666-5000= 6666
11.) search for 6666 in our files u will get in reformat3
12.) now search for O/P number in reformat3, u will get 2222
13.) add 5000, 7222 . Search in XXGFlow , u got 12777.
14.) sub 5000 , u got 7777, search for 7777 in our files , it is Output_File
15.) job done.

Now in Input_File_f , we have
i/p1,join2,reformat3,output

Got it???

I just mentioned a small example , we can have n number of I/P files , many other files and may be more than one O/P files(im some cases we will have more than one O/P files).

So dude this is what i need.
I want u to be very clear abt this, bcz mostly dependent on u.
If u have still any doubts , come back to me.
Just for now get to know abt logic and then i'll tell u the key words for every number (I/P and O/P) and then we will try to figure it out.

I know it is a little bit difficult bcz even for me it took 1.5 month to figure it out. basically my need is:

I am working in Ab initio tool (some GE tool) , it stores every thing in unix.
Now i am in a situation to automate some thing , so i analysed how a gaph is stored in unix , how is it interpretating. At present we are now in the stage of scripting what i analysed and need.


Thanks a lot for ur patience

Hey pls find zip file
I have zipped main document only , if this post got published then , i'll send u the commands whcih needed to be run

Hey pls find zip file
I have zipped main document only , if this post got published then , i'll send u the commands whcih needed to be run

---------- Post updated at 01:19 PM ---------- Previous update was at 01:04 PM ----------

First run this code:

Code:

 
awk -F "\\\.mdc\||\\\.mpc\||\\\.mp\|" '{if($0~/Layout\|\$\[\[recor/){if(fn && s){print s > fn;s=$0;}else{s=$0}}
else if(NF > 1 && $0 ~ /Ab Initio/){n=split($1,a,"\\");x++;fn=a[n]x;{s=s"\n"$0}}
else if($0 ~ /PROJECT_DIR|serial\/lookup/){fn="lookup"x;s=s"\n"$o}
else if(s){s=s"\n"$0}
}END{print s > fn}' temp1.txt

U will get around 101 files generated.Observe 3 Output_Files will be there.
Now run the below:

Code:

 
ls > File_name_temp

Code:

 
while read line
do
if [[ $(awk '/PROJECT_DIR/ && /serial\/lookup/' $line) ]]
then
file_name="lookup"$(echo $line | sed 's/[a-zA-Z]//g')
echo $file_name
mv $line $file_name
fi
done<File_name_temp

Now you will find only one Output_File.

Code:

 
cat temp1.txt | grep "{2010210004|XXGflow|">xxgflow.txt

Now u will have a file to know the flows(I already mentioned about this in previous posts, this is to trace the components flow)

If every thing works fine , get back to me.
If not working also we will discuss

---------- Post updated at 03:07 PM ---------- Previous update was at 01:19 PM ----------

//logic:

so in loop u can have a count of input files and take that particular number every time.

Code:

ls | grep "Input_File" | wc -l
26

Now loop should for 26 time each time taking Input_File



for(i=0;i<26;i++)
{
//logic//
}

//logic: is mentioned above in quotes .
Get back to me for any issues.