Shell Programming and Scripting

Hello.
I have a long list of data which has the following structure
The number shows the unique identity of the word. And all homophones are clustered with the same number ID.
An example will make this clear
The awk script I have allows conversion of a list to row but on condition that each cluster is separated by a Hard return.

Code:

# script to convert a list of names to a row
BEGIN{FS="="}
NF==0{f=0;printf "\n";next}{if(f==1){printf "="$1}else{f=1;printf $1}}

Unluckily this is not the case here. I have tried to modify it such that a database of the type above can be clustered together. The expected output would be:
How do I modify the script such that the output above is generated and all homographs belonging to the same numerical ID are clustered together.
I have tried to adapt the script but without much success.
Many thanks

Code:

BEGIN{FS="=";}
{if (!a[$1]) a[$1]=$1; a[$1]=a[$1] "=" $2;}
END {for(i in a) print a[i];}

Many thanks. It worked beautifully.
I understood the logic (most important) My only query:

Code:

BEGIN{FS="=";}

Wnat does the semi-colon do after the file delimiter. I normally write:

Code:

BEGIN{FS="="}

The script gives the same output both with and without the semi-colon.
Does the semi-colon bring in any change

The ";" in awk is code line delimeter. End of line, ";", or closing "}" perform the same function in awk.

The BEGIN statements shown perform the same function.

Many thanks. I will rememeber that when I write the first "invocation".