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Format output in AWK command

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# 1  
Old 09-27-2012
Question Format output in AWK command

hi Friends ,

I have a file as below



header for both files is common


to compare 2 files i have used the following code

paste -d '~' s.txt t.txt | awk -F '~' '{c=NF/2;for(i=1;i<=c;i++)if($i!=$(i+c))printf "line %-5s field %s orginal %s changed  %s\n",NR,i-1,$i,$(i+c)}'

I got output as

line 2     field 1 orginal 6 changed  5
line 2     field 2 orginal  changed  8
line 3     field 3 orginal 9 changed  7

But i am unable to find the solution to make my script inculde the header information in the output file. Plz help me. your help is much appreciated.

2  ~ DIS      ~   6       ~    5
2  ~ NOT      ~          ~     8
3  ~ KAT      ~    9     ~     7

# 2  
Old 09-27-2012
Assuming only 1 line in header.txt, try:
awk -F'~' -v header="$(<header.txt)" 'BEGIN{OFS=" ~ ";split(header,h)
FNR==NR{for(i=1;i<=NF;i++) e[FNR,i]=$i;next}
   print FNR,h[i],e[FNR,i],$i
}' s.txt t.txt

# 3  
Old 09-27-2012
@Elixir . Thanks for the reply. Smilie you made my day. Smilie it is working as Expected.

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