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Shell Programming and Scripting

pattern searching

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# 15  
Old 09-19-2012
now it print out extra characters after the date

Code:
$ for i in `ls -1 *.jar`;do echo $i|sed -n "s/.*_\([0-9]\{8\}.*\).jar$/\1/p" ;done|more
20120727
20120711
20120711_1
20120712
20120712_1
20120713
20120713_1
20120714
20120714_1
20120715
20120715_1
20120716
20120716_1
20120717
20120717_1
20120718
20120718_1
20120719
20120719_1
20120720
20120720_1
20120721
20120721_1
20120722
20120722_1
20120723
20120723_1
20120724
20120724_1
20120725
20120725_1
20120726

sorry for troubling you Smilie

---------- Post updated at 10:17 PM ---------- Previous update was at 10:12 PM ----------

cant I say extract the date part from the last characters of the string:


awk lets me substr characters from the start of the string..how about substr characters from the end of the string, with the last character as the first character

Moderator's Comments:
Mod Comment Please view this code tag video for how to use code tags when posting code and data.
Last edited by vbe; 09-19-2012 at 01:57 PM..
# 16  
Old 09-19-2012
I thought you wanted that extra character. Well all you have to do is tweak the regular expression:
Code:
sed -n "s/.*_\([0-9]\{8\}\).*\.jar$/\1/p"

# 17  
Old 09-19-2012
Quote:
Originally Posted by gary_w
I thought you wanted that extra character. Well all you have to do is tweak the regular expression:
Code:
sed -n "s/.*_\([0-9]\{8\}\).*\.jar$/\1/p"

thank you thank you thank you..please explain to me the regular expression..i have been trying to get hold of this since long..but have only managed to bang my head
# 18  
Old 09-19-2012
From left to right:
Code:
sed -n "s/.*_\([0-9]\{8\}\).*\.jar$/\1/p"

Code:
sed   - Stream editor
-n    - Suppress normal action which is to print all lines
"s/   - Start search/replace pattern
.     - Match any character
*     - and any number of any character
_     - followed by an underscore
\(    - Start first group (this portion of the search pattern, if found, can be referred to later)
[0-9] - followed by a single number in the range of 0-9
\{8\} - followed by 8 instances of the previous pattern (a number)
\)    - End the first group
.*    - followed by any character and any number of any character
\.    - followed by a period (escaped with a backslash since the period
        has special meaning in a regex)
jar   - followed by the string "jar"
$     - followed by the end of the line
/     - Start replace pattern
\1    - Refers to the first group as defined inside the \(  \)
/     - End replace string
p     - Don't replace, but print the match instead
"     - End the sed pattern

This User Gave Thanks to gary_w For This Post:
danish0909
# 19  
Old 09-19-2012
ok!, so basically what comes inside the
Quote:
\( and \)
gets printed on the screen. great thanks for letting it out so cleanly. thanks a lot
# 20  
Old 09-19-2012
Technically it gets printed to standard output (STDOUT). That's how you are able to capture it in a variable.

You're welcome!
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