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Shell Programming and Scripting

Convert few columns to rows

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# 1  
Old 09-19-2012
Convert few columns to rows
Hi!
Does anybody help me in converting following data:

INPUT looks like this:
Code:
20. 100.        
30  200.
40. 400.
50. 100.        
60.  200.
70. 400.
80. 200.
150. 210.
30. 100.

OUTPUT should look like this:
Code:
20. 100.     30  200.   40. 400.    50. 100.        
60.  200.     70. 400.   80. 200.   150. 210.
30. 100.

Thanks a lot for your help!
Last edited by Franklin52; 09-19-2012 at 06:42 AM.. Reason: Please use code tags for data and code samples
# 2  
Old 09-19-2012
Assuming your input is same as you have provided..

Code:
xargs -n 8 < file

This User Gave Thanks to pamu For This Post:
lovelinux
# 3  
Old 09-19-2012
Simplest what one can do is..

Code:
 
printf "%s %s %s %s %s %s %s %s\n" $(cat filename)

This User Gave Thanks to vidyadhar85 For This Post:
lovelinux
# 4  
Old 09-19-2012
It works but I would like to have %8.2f for each value. Thanks!

---------- Post updated at 06:17 AM ---------- Previous update was at 05:12 AM ----------

Quote:
Originally Posted by vidyadhar85
Simplest what one can do is..

Code:
 
printf "%s %s %s %s %s %s %s %s\n" $(cat filename)

Wonderful its very simple, In case if I have only 2 values left in the last row it is simply writing zeros in other 6 places. If I use a conditional statement qual to NF it will work.
# 5  
Old 09-19-2012
Quote:
Originally Posted by lovelinux
simply writing zeros in other 6 places.
Try this..
I know this is not the best way. you have to handle some spacing...Smilie

Code:
xargs -n 8 < file | awk '{if(! max){max=NF}{for(i=1;i<=max;i++){if($i == ""){ $i=0}}}}1'

# 6  
Old 09-19-2012
Quote:
Originally Posted by pamu
Try this..
I know this is not the best way. you have to handle some spacing...Smilie

Code:
xargs -n 8 < file | awk '{if(! max){max=NF}{for(i=1;i<=max;i++){if($i == ""){ $i=0}}}}1'


first of all Thanks! unfortunately, I still have zeros at the end.

---------- Post updated at 08:19 AM ---------- Previous update was at 07:08 AM ----------

Here is the working script
Code:
awk 'BEGIN {
i = 1}
{
printf "%8.2e %8.2e ", $1,$2
i = i+1
if (i == 5)
{
i=1; printf "\n" 
}
}
END {
}' file

Last edited by radoulov; 09-19-2012 at 10:37 AM..
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