perl regular expression deal with $


 
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# 1  
Old 09-18-2012
perl regular expression deal with $

Dear All,

Code:
#!/usr/bin/perl
use strict;
use warnings;

my $tmp = $ARGV[0];

if ($tmp =~ s/[\ \$]//g > 0) {
        print "yes\n"
} else {
        print "no\n";
}

Output is:
Code:
./master.pl " 333"
yes
./master.pl "$333"
no

why cannot detect the $ sign? please advise.

Thanks
# 2  
Old 09-18-2012
scape the $ in the command line. The script thinks $3 as a variable.
# 3  
Old 09-18-2012
I cannot scape $ in the $ARGV as this is from customer input...

how to detect customer input $ infront of the string. Smilie
# 4  
Old 09-18-2012
Code:
 
./master.pl '$333'

This User Gave Thanks to rdrtx1 For This Post:
# 5  
Old 09-18-2012
sorry got your requirement wrong..try rdrtx1's solution...edited my code by removing it

Quote:
Originally Posted by jimmy_y
Dear All,

Code:
#!/usr/bin/perl
use strict;
use warnings;

my $tmp = $ARGV[0];

if ($tmp =~ s/[\ \$]//g > 0) {
        print "yes\n"
} else {
        print "no\n";
}

Output is:
Code:
./master.pl " 333"
yes
./master.pl "$333"
no

why cannot detect the $ sign? please advise.

Thanks
This User Gave Thanks to msabhi For This Post:
# 6  
Old 09-18-2012
Thanks, got the point single quote
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