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LINUX ---> Add one date to a date variable

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# 1  
Old 09-10-2012
LINUX ---> Add one date to a date variable
Hi All,

I am trying to add one day to the busdt variable i am extracting from a file (DynamicParam.env). I am deriving the busdt as below.

Quote:
export busdt=`cat $COMMON_SCRIPTS/DynamicParam.env | grep 'P_BUS_DATE' | cut -d"=" -f2`
Is there any function which I can use to derive as below.

If busdt=20120910, then the new derived variable value should be 20120911
If busdt=20120930, then the new derived variable value should be 20121001

Thanks Much in advance.
Freddie
# 2  
Old 09-10-2012
Code:
busdt=`cat $COMMON_SCRIPTS/DynamicParam.env | grep 'P_BUS_DATE' | cut -d"=" -f2`
export busdt=`date -d "$busdt +1day" +%Y%m%d`

--
Bye
# 3  
Old 09-11-2012
Hi dsfreddie,


Try the below command to get the next day's date
Code:
busdt=`date --date='tomorrow' +%Y%m%d`

Last edited by Franklin52; 09-11-2012 at 04:25 AM.. Reason: Please use code tags for data and code samples
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