conversion of loop in perl


 
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# 1  
Old 08-28-2012
conversion of loop in perl

Hello Sir,

How can i convert below two loop lines in perl

Code:
 for BLOCK in /sys/block/myblock[a-z]*

Code:
 for BLOCK in /dev/myblock[a-z]*

How i can write them in perl like

Code:
 foreach( </sys/block/myblock[a-z]*/queue/nr_requests> )

# 2  
Old 08-28-2012
You could use the glob operator, however while character classes are available specifying multiple occurrences isn't available so you'd have to perform the character class check within the loop.
Code:
for my $block (glob 'sys/block/myblock*'){
  if ($block=~(^/sys/block/myblock[a-z]*$)){
    ...
  }
}

# 3  
Old 08-28-2012
Below code is also fine, please confirm.

for my $block (glob '/dev/myblock*'){
if ($block=~(^/dev/myblock[a-z]*$)){
...
}
}
# 4  
Old 08-28-2012
Yes, the same pattern applies
# 5  
Old 08-28-2012
Please confirm below code is fine.

Code:
for my $block (glob '/dev/myblock*'){
  if ($block=~(^/dev/myblock[a-z]*$)){
system("blockdev --setra 16384 $_");

  }
}

# 6  
Old 08-28-2012
Install perl and try it yourself.

If you're unable to do so, this looks less like practical questions and more like homework.
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