build array name based on loop index


 
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# 1  
Old 08-23-2012
build array name based on loop index

Hi,
I am new to perl and I have the following query please help here.

I have following array variables declaration
Code:
@pld1 = qw(00 01 02 03 04 05);
@pld2 = qw(10 11 12 13 14 15);
 
for(my $k=1;$k<=2;$k++)
{
   //I want here to use @pld1 if $k is 1
   // and @pld2 if $k is 2. How to do that ????
   //I have user defined function 'send' below
 
   send(@pld$k);
    
}

but the above function giving syntax error. how to substitute $k so that I send @pld1 when $k is 1 and @pld2 when $k is 2.



Thanks
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Last edited by vbe; 08-23-2012 at 09:49 AM..
# 2  
Old 08-23-2012
use:

Code:
eval  "&sendK(\@pld$k)" ;

# 3  
Old 08-23-2012
You could also use a single, two-dimensional, array, or array references, since perl supports complex data structures.
# 4  
Old 09-03-2012
Hi Klashxx,
That worked. Thanks a lot.

Thanks
Jana
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