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Shell Programming and Scripting

Compare two text files and output difference

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# 8  
Old 08-24-2012
Hi Don, thanks again for the help...

The following is what I currently have :

Code:
#!/bin/sh
# Shell Script to compare file 1 and file 2 and print differences to file 3


# Tool number
toolnr=`uname -n | cut -c2-`

# Log Directory Path
LOG_path="/usr/asm/atl.1001/user_data/error_logs"

# Input file names
file1="ASML_LOGBOOK.TXT"
file2="ASML_LOGBOOK_2.TXT"

diff ${file1} ${file2} |awk '!/^</ {next} {sub(/^../,"");print}' > ${LOG_path}/LOG1001.TXT

When I run this i get a message saying
awk: syntax error near line 1
awk: illegal statement near line 1

Am I running this in the wrong shell?

I tried changing the first line to
Code:
#!bin/awk

But that gives error messages stating the same as above but for line 6, so I remove that variable line from the code and just write the output file name in by hand at the end but then I get an error same as above for line 10.

Im guessing I have one fundamental issue here that someone with any kind of knowledge in scripting would avoidSmilie!

M
# 9  
Old 08-24-2012
Quote:
Originally Posted by martin0852
Hi Don, thanks again for the help...

The following is what I currently have :

Code:
#!/bin/sh
# Shell Script to compare file 1 and file 2 and print differences to file 3


# Tool number
toolnr=`uname -n | cut -c2-`

# Log Directory Path
LOG_path="/usr/asm/atl.1001/user_data/error_logs"

# Input file names
file1="ASML_LOGBOOK.TXT"
file2="ASML_LOGBOOK_2.TXT"

diff ${file1} ${file2} |awk '!/^</ {next} {sub(/^../,"");print}' > ${LOG_path}/LOG1001.TXT

When I run this i get a message saying
awk: syntax error near line 1
awk: illegal statement near line 1

Am I running this in the wrong shell?
I tried this script on my system (running OS X) using #!/bin/sh, #!/bin/bash, and #!/bin/ksh and all three worked just fine (after changing the setting of LOG_path to a directory that exists on my system. It won't work with csh or tcsh.

Quote:
Originally Posted by martin0852
I tried changing the first line to
Code:
#!bin/awk

But that gives error messages stating the same as above but for line 6, so I remove that variable line from the code and just write the output file name in by hand at the end but then I get an error same as above for line 10.

Im guessing I have one fundamental issue here that someone with any kind of knowledge in scripting would avoidSmilie!

M
This is a shell command language script and awk is not a shell command language interpreter, so (as you have found) using /bin/awk as your command interpreter doesn't work.

What operating system are you using? I.e., what is the output from the command uname -a on your system.
# 10  
Old 08-25-2012
Hi Don, just checked the output of
Code:
uname -a

and the following is what I get:

SunOS mxxxx 5.10 where mxxxx is the machine number.

So i looked up the awk command on solaris and i replaced the awk command with /usr/xpg4/bin/awk and it seems to work perfectly!!

the following is my code that does exactly what I want to:

Code:
#!/bin/sh
# Shell Script to compare file 1 and file 2 and print differences to file 3


# Tool number
toolnr=`uname -n | cut -c2-`

# Log Directory Path
LOG_path="/usr/asm/atl.1001/user_data/error_logs"

# Input file names
file1="ASML_LOGBOOK.TXT"
file2="ASML_LOGBOOK_2.TXT"

diff ${file1} ${file2} |/usr/xpg4/bin/awk '!/^</ {next} {sub(/^../,"");print}' > ${LOG_path}/LOG${toolnr}.TXT

I'm pretty sure this will do exactly what I want.

Thanks very much for the help!
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