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# 8  
Old 08-20-2012
You did not answer, why it must be awk as stated in the subject.

Count from the start of the string and check what character is at position 4 while keeping in mind, that "n" stands for numeric. The 1 should explain itself as no delimeter is defined.
# 9  
Old 08-20-2012
Quote:
Originally Posted by zaxxon
You did not answer, why it must be awk as stated in the subject.

Count from the start of the string and check what character is at position 4 while keeping in mind, that "n" stands for numeric. The 1 should explain itself as no delimeter is defined.
Thanks for the explaination. I use awk becasue I think awk can do this thing, I may get some learning point from the "awk answer" Smilie
# 10  
Old 08-20-2012
Quote:
Originally Posted by yanglei_fage
I use awk becasue I think awk can do this thing, I may get some learning point from the "awk answer" Smilie
You could do it in AWK, but you would essentially be reimplementing sort (read, compare, sort, output). If you think there's something to be learned from that exercise, it would defeat its purpose if we did it for you.

Regards,
Alister
This User Gave Thanks to alister For This Post:
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