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To Check whether the Input is a Year or Not?


 
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# 1  
Old 08-06-2012
To Check whether the Input is a Year or Not?

Hi Guys

I have a Requirement that the input will be given and i have to check whether the input is a Year or not.

For Example

2004,2009 and so on forth will be considered a year and anything else like
12:15 or else will not be.

Have built the below Code


Code:
set -x

echo " Enter the Variable to be tested"
read Test_Var

case $Test_Var in

[1000-9999] )  echo "It is a Year";;
 * )           echo "Is is not a Year";;
esac

But everything is going to the "Not Year" Part.

I am little bit new to Shell Scripting. So needed your Help.


Regards
Ajesh


Moderator's Comments:
Mod Comment Please use code tags next time for your code and data.

Last edited by zaxxon; 08-06-2012 at 05:22 AM.. Reason: code tags
# 2  
Old 08-06-2012
Code:
case $Test_Var in
[1-9][0-9][0-9][0-9] )  echo "It is a Year";;
                   * )  echo "Is is not a Year";;
esac

This User Gave Thanks to balajesuri For This Post:
# 3  
Old 08-06-2012
Try
Code:
case $Test_Var in  
    [1-9][0-9][0-9][0-9] )  echo "It is a Year";; 
     * )           echo "Is is not a Year";;
esac

This User Gave Thanks to hergp For This Post:
# 4  
Old 08-06-2012
Bug try this.....

Code:
echo " Enter the Variable to be tested"
read Test_Var

if [[ "$Test_Var" -gt 999  && "$Test_Var" -lt 10000 ]]
then
echo "It is a Year";
else
echo "Is is not a Year";
fi

# 5  
Old 08-06-2012
Simultaneous post Smilie
# 6  
Old 08-06-2012
I had tried that but when it comes to a symbol lile ; or >>. the Shell gives a compilation Error while running.

Thanks Anyway


Quote:
Originally Posted by pamu
Code:
echo " Enter the Variable to be tested"
read Test_Var

if [[ "$Test_Var" -gt 999  && "$Test_Var" -lt 10000 ]]
then
echo "It is a Year";
else
echo "Is is not a Year";
fi

# 7  
Old 08-06-2012
Note that
Code:
case $Test_Var in

[1000-9999] )  echo "It is a Year";;
 * )           echo "Is is not a Year";;
esac

will match a single character that is 1, 0, 0, any single digit in the range 0 through 9, 9, 9, or 9. So if Test_var had been set to "6", it would say it is a year. Bracket expressions don't look for ranges of numeric values.

Hope this helps you understand what was going wrong.

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