Shell Programming and Scripting

Hi Guys,

I have a file with content as below

aj.txt

Code:

"Iam
allfine" abcdef
abcd "all is 
not well"

What I'm trying to say is my data has some new line characters in between quoted text. I must get ride of the newline character that comes in between the quoted text.

output must be:

Code:

"Iamallfine" abcdef
abcd "all is not well"

the machine has SUN OS in it. only korn shell.

please help.

Regards,
Aj

Try:

Code:

/usr/xpg4/bin/awk '(NR-1)%2{$1=$1}1' RS=\" ORS=\" infile

It worked fine. It would be a great help if you can explain it a bit

It worked !!
Attached are the Screenshots!
onlt thing is ther is an extra line in the output with a " in it

please can you explain it. I didn't understand the code.

Yes, I guess it may appear a bit cryptic..

It uses a double quote as input and output record selector (RS=\" ORS=\"). So any record is either inside or outside double quotes. The mod of the line number divided by 2 ( (NR-1)%2 ) determines which is the case. If it is the case then $1=$1 is used to replace any occurrence of the default input field selector (FS), i.e. any combination of consecutive spaces, TABs or newlines to be replaced by the default output field selector (OFS), which is a single space...
The 1 is synonymous for "print the record"..

If it is a matter of just joining every two lines, then this might work too:

Code:

paste -d " " - - < infile

oops an issue again !!

Code:

/usr/xpg4/bin/awk '(NR-1)%2{$1=$1}1' RS=\" ORS=\" STD_H.txt > STD_TRUE.txt

/usr/xpg4/bin/awk: line 0 (NR=1561): Record too long (LIMIT: 19999 bytes)