Shell Programming and Scripting

# ps |awk '{if($1>=5) {$1=$1; found=1; print}} END {exit !found}' OFS="\t"; echo "exit code: "$?  
5       S       root    972     1       ...
5       S       root    1504    1       ...
exit code: 0
# ps |awk '{if($1>=6) {$1=$1; found=1; print}} END {exit !found}' OFS="\t"; echo "exit code: "$?
exit code: 1

ps ...  |awk '
{if($5>=2)
 {$1=$1;
  found=1;
   print}}
END {exit !found}'

awk

awk: syntax error near line 6
awk: illegal statement near line 6

exit [expr]     # skip the rest of the input; exit status is expr

ps -eo pri,pid,user,nice,pcpu,comm | awk '{if($5>=5) {$1=$1; found=1; print}} END {exit found}' OFS="\t"; echo "exit code: "$? 
20\10833\root\20\12.4\/apps/progress//bin/_progres
30\14631\root\20\10.7\_progres
20\19628\root\20\10.5\_progres
exit code: 1

awk 'BEGIN {found=1} {if($5>=5) {$1=$1; found=0; print}} END {exit found}' OFS="        ";