I am new to BASH scripting and I was wondering if anyone could have a look at this code and explain to me why I am getting an Unexpected End of File Error ?
If you can that would be great / much appreciated! THANKS!
Code:
#!/bin/bash
USER=""
PASS=""
if [ -z "$PASS" ]; then echo "You need to set your username and password in the script."; exit 1; fi
wget -q -O .login.html http://www.hackthissite.org/user/login --post-data="username=$USER&password=$PASS&btn_submit=Login" --save-cookies=.cookies.txt --keep-session-cookies --referer http://www.hackthissite.org/
grep "Image Validation" .login.html >/dev/null && echo "Error: You need to log out/in in a web browser" && exit 1
wget -q -O - http://www.hackthissite.org/missions/prog/11/ --load-cookies=.cookies.txt --keep-session-cookies --referer http://www.hackthissite.org/missions/programming/ > out.txt
TEXT=`cat out.txt | grep "Generated String:" | cut -f 2 -d : | cut -f 1 -d "<" | tr -d [:blank:]`
SHIFT=`cat out.txt | grep "Generated String:" | cut -f 3 -d : | cut -f 1 -d "<" | tr -d [:blank:]`
echo "If this doesn't work, you'll need to add this separator:"
echo $TEXT
for EACH in `echo $TEXT | tr "," "\n" | tr ")" "\n" | tr "#" "\n"| tr "'" "\n"| tr "." "\n"| tr "&" "\n"| tr "(" "\n"| tr "!" "\n"| tr "%" "\n"| tr "$" "\n"| tr "+" "\n"| tr "-" "\n"| tr "/" "\n"| tr "*" "\n"| tr "@" "\n"| tr "^" "\n"| tr "\"" "\n"`
do
let EACH=$EACH-$SHIFT
STRING="$STRING$(printf "\\$(printf "%03o" $EACH)")"
done
echo The string is $STRING
wget -q -O - http://www.hackthissite.org/missions/prog/11/index.php --post-data="solution=$STRING" --load-cookies=.cookies.txt --keep-session-cookies --referer http://www.hackthissite.org/missions/prog/11/ > out2.txt
grep "answer is wrong" out2.txt | html2text
grep -i "successfully" out2.txt | html2text
grep -i "already completed" out2.txt | html2text
rm .login.html; rm .cookies.txt; rm out.txt; rm out2.txt
There are is no line containing << so I think that we are looking for a corrupt script.
Please re-post the script after examining it with this sed command which makes control codes visible:
Code:
sed -n l scriptname
A normal unix/Linux line terminator will show as a dollar sign.
Please post what Operating System and version you are running.
Ps: I can't follow the logic or reasoning behind the code, but I don't like the look of this line:
Ignoring quote a lot of the code, why no double quotes round $TEXT if it can contain Shell Special Characters? Try putting double-quotes round every string variable in this script. What in words is the line intended to do? The tr commands can be condensed into a single tr command enclosed in single quotes (to stop the Shell reacting to Shell Special Characters).
Something like (untested):
Code:
for EACH in `echo "${TEXT}"|tr ',)#".&(!%$+-/*@^\' '\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n'`
Ps. In my experience it is better to test for the valid characters than to try to eliminate the invalid characters.
Hi,
I am brand new to this so I apologize ahead of time for any formatting problems.
I know there is a previous (closed) thread on here about this problem but I wasn't able to fix the error following the posts there so I thought I could create a new one.
Here is the error I am getting:
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done
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