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remove caret (^) symbol from pattern using sed

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# 1  
Old 07-13-2012
remove caret (^) symbol from pattern using sed
Hi,

I am trying to remove the caret symbol from a bash variable. This is the variable:
Code:
var="GOTAN^TOK^B"

and this is the code I am trying to use to remove the caret symbol:
Code:
nocarrot=`echo $var | sed -e 's/^/_/g'`

This is the output intended (but not acheived with the above function):
Code:
GOTAN_TOK_B

Please help. Thanks in advance.
# 2  
Old 07-13-2012
Code:
echo "GOTAN^TOK^B" | sed 's/\^/_/g'

You just needed to escape ^, since it has special meaning in regular expressions (Start of line or not).
# 3  
Old 07-13-2012
Use a "\" to escape its normal behavior of pointing to the start of the line/word.
Code:
nocarrot=`echo $var | sed -e 's/\^/_/g'`

This User Gave Thanks to aster007 For This Post:
shaan4uster
# 4  
Old 07-13-2012
echo ${var//^/_}
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