I've been stuck for several days on this. Using grep on a command line, I can use quotes, eg...
Code:
grep 'pattern of several words' filename
I want to do this in my bash script. In my script I have captured the several command line arguments (eg arg1 arg2) into a variable:
Code:
variable=$@
I guess this is an array variable consisting of arg1, arg2 etc. I try to use it later on data piped into grep...
Code:
cat file | grep $variable
This doesn't work -- grep sees arg1 and arg2 of my variable separately and interprets it as 'grep pattern[arg1] filename[arg2]'. Consequently it errors saying "file [arg2] not found".
So I tried using quotes on the script line, as I would on the command line...
Code:
cat file | grep '$variable'
but it then seems to treat $variable literally and greps on the actual name of the string, so returns no results.
I've tried backslashed quotes....
Code:
cat file | grep \'$variable\'
but that doesn't work either, it thinks arg2 is a filename again.
Any ideas on the way to do this?
Thanks,
Adrian.
Last edited by Franklin52; 07-11-2012 at 05:36 PM..
Reason: Please use code tags for data and code samples, thank you
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